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In this question, assume all dimensions are in centimetres - OCR - GCSE Maths - Question 13 - 2018 - Paper 1

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In this question, assume all dimensions are in centimetres. Jess and Pete have many rectangular tiles. Each tile has length $a + b$ and width $2b$. (a) Jess joins ... show full transcript

Worked Solution & Example Answer:In this question, assume all dimensions are in centimetres - OCR - GCSE Maths - Question 13 - 2018 - Paper 1

Step 1

Write an expression for the perimeter of her rectangle.

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Answer

To find the perimeter of a rectangle, we use the formula:

P=2(l+w)P = 2(l + w)

In Jess's case, the length is the total length of three tiles, which is: extLength=3(a+b) ext{Length} = 3(a + b) And the width is: extWidth=2b ext{Width} = 2b

Thus, the perimeter can be expressed as:

P=2(3(a+b)+2b)=2(3a+3b+2b)=2(3a+5b)=6a+10b.P = 2(3(a + b) + 2b) = 2(3a + 3b + 2b) = 2(3a + 5b) = 6a + 10b.

Step 2

An expression for the area of her rectangle is $6ab + 6b^2$. Factorise this expression fully.

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Answer

To factor the expression 6ab+6b26ab + 6b^2, we can factor out the common term:

6ab+6b2=6b(a+b).6ab + 6b^2 = 6b(a + b).

Step 3

Draw a possible arrangement of tiles for Pete's rectangle.

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Answer

A possible arrangement for Pete's rectangle using the tiles would be:

  • 4 tiles arranged in a row, giving:

extLength=4(a+b),extWidth=2b. ext{Length} = 4(a + b), ext{Width} = 2b.

Step 4

Write down expressions for the length and the width of the rectangle.

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Answer

For Pete's rectangle, the expressions are:

  • Length: 4(a+b)4(a + b)
  • Width: 2b.2b.

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