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The diagram shows a pyramid ABCDE - OCR - GCSE Maths - Question 17 - 2021 - Paper 1

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The diagram shows a pyramid ABCDE. The pyramid has a square horizontal base ABCD with side 5.6 cm. The vertex E is vertically above the centre O of the base. The h... show full transcript

Worked Solution & Example Answer:The diagram shows a pyramid ABCDE - OCR - GCSE Maths - Question 17 - 2021 - Paper 1

Step 1

Calculate the Area of Base ABCD

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Answer

Since ABCD is a square with a side length of 5.6 cm, the area of the base can be calculated using the formula:

Abase=side2=(5.6extcm)2=31.36extcm2A_{base} = side^2 = (5.6 ext{ cm})^2 = 31.36 ext{ cm}^2

Step 2

Calculate the Area of Triangular Faces

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Each triangular face (e.g., triangle ABE) has a base equal to the side of the square base and a height that can be calculated using the Pythagorean theorem.

The height of each triangle can be found as follows:

  • The length from the center O to a vertex (e.g., A) is half the diagonal of the square base: d = rac{ ext{side} imes ext{surd}(2)}{2} = rac{5.6 ext{ cm} imes ext{1.414}}{2} \ ext{(approximately 3.94 cm)}

  • The height of the triangle can then be determined with: htriangle=extsurd(OE2+OA2)=extsurd((6.8extcm)2+(3.94extcm)2)  htriangle≈7.85extcmh_{triangle} = ext{surd}(OE^2 + OA^2) = ext{surd}((6.8 ext{ cm})^2 + (3.94 ext{ cm})^2) \ \ h_{triangle} \approx 7.85 ext{ cm}.

Now, calculate the area of one triangular face: Atriangle=12×base×height=12×5.6extcm×7.85extcm≈21.96extcm2A_{triangle} = \frac{1}{2} \times base \times height = \frac{1}{2} \times 5.6 ext{ cm} \times 7.85 ext{ cm} \approx 21.96 ext{ cm}^2

Step 3

Total Surface Area of the Pyramid

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Answer

Since there are 4 triangular faces: A_{total aces} = 4 \times A_{triangle} \approx 4 \times 21.96 ext{ cm}^2 = 87.84 ext{ cm}^2

Finally, the total surface area is: ext{Surface Area} = A_{base} + A_{total aces} \approx 31.36 ext{ cm}^2 + 87.84 ext{ cm}^2 \approx 119.20 ext{ cm}^2

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