Two variables, x and y, are connected by the equation y = kx^n - Scottish Highers Maths - Question 9 - 2017
Question 9
Two variables, x and y, are connected by the equation y = kx^n.
The graph of log_2 y against log_2 x is a straight line as shown.
Find the values of k and n.
Worked Solution & Example Answer:Two variables, x and y, are connected by the equation y = kx^n - Scottish Highers Maths - Question 9 - 2017
Step 1
State linear equation
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Answer
From the given equation, we can express it in a logarithmic form:
ext{Let } y &= kx^n \\
ext{Taking log on both sides:} \\
ext{log_2 y} &= ext{log_2(kx^n)} \\
&= ext{log_2 k} + n ext{log_2 x}
ext{This represents a linear equation of the form:} \\
ext{log_2 y} = n ext{log_2 x} + ext{log_2 k}
ext{where the gradient is } n ext{ and the y-intercept is log_2 k.}
\end{align*}$$
Step 2
Use the graph to find the y-intercept
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Answer
From the graph, the y-intercept is at y = -12 when log_2 x = 0. Thus,
extlog2k=−12
To express k in exponential form, we rewrite:
k=2−12
Step 3
Identify the gradient from the graph
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Answer
The gradient of the line from the graph is identified as 3. Thus,
n=3
Step 4
State k and n
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Answer
Finally, combining our results gives:
k=2−12n=3
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