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Two variables, x and y, are connected by the equation y = kx^n - Scottish Highers Maths - Question 9 - 2017

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Question 9

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Two variables, x and y, are connected by the equation y = kx^n. The graph of log_2 y against log_2 x is a straight line as shown. Find the values of k and n.

Worked Solution & Example Answer:Two variables, x and y, are connected by the equation y = kx^n - Scottish Highers Maths - Question 9 - 2017

Step 1

State linear equation

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Answer

From the given equation, we can express it in a logarithmic form:

ext{Let } y &= kx^n \\ ext{Taking log on both sides:} \\ ext{log_2 y} &= ext{log_2(kx^n)} \\ &= ext{log_2 k} + n ext{log_2 x} ext{This represents a linear equation of the form:} \\ ext{log_2 y} = n ext{log_2 x} + ext{log_2 k} ext{where the gradient is } n ext{ and the y-intercept is log_2 k.} \end{align*}$$

Step 2

Use the graph to find the y-intercept

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Answer

From the graph, the y-intercept is at y = -12 when log_2 x = 0. Thus,

extlog2k=12 ext{log_2 k} = -12

To express k in exponential form, we rewrite:

k=212k = 2^{-12}

Step 3

Identify the gradient from the graph

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Answer

The gradient of the line from the graph is identified as 3. Thus,

n=3n = 3

Step 4

State k and n

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Answer

Finally, combining our results gives:

k=212n=3k = 2^{-12} \\ n = 3

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