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In a forest, the population of a species of mouse is falling by 2.7% each year - Scottish Highers Maths - Question 4 - 2019

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In a forest, the population of a species of mouse is falling by 2.7% each year. To increase the population scientists plan to release 30 mice into the forest at the ... show full transcript

Worked Solution & Example Answer:In a forest, the population of a species of mouse is falling by 2.7% each year - Scottish Highers Maths - Question 4 - 2019

Step 1

State the values of a and b

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Answer

From the problem, we know that the mouse population decreases by 2.7% each year. Therefore, the factor by which the population decreases can be represented as:

a=10.027=0.973a = 1 - 0.027 = 0.973

Additionally, 30 mice are released each year, which means:

b=30b = 30

So, the values are:

  • a=0.973a = 0.973
  • b=30b = 30

Step 2

Explain why the estimated population of mice will stabilise in the long term

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Answer

The estimated population of mice will stabilise in the long term because the recurrence relation is linear and involves a constant addition of 30 mice to the decreasing population. As the population falls by a fixed percentage (2.7%), the balance between losses due to natural decline and gains from the release of new mice (30 each year) will ultimately result in a stable long-term population.

Step 3

Calculate the long term population to the nearest hundred

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Answer

To find the long-term population, we need to determine the limit of the recurrence relation as nn approaches infinity. We can denote the long-term population as:

L=0.973L+30L = 0.973L + 30

Rearranging gives:

L0.973L=30L - 0.973L = 30 0.027L=300.027L = 30 L=300.0271111.11L = \frac{30}{0.027} \approx 1111.11

Rounding to the nearest hundred, the long-term population stabilises at approximately 1100.

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