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For a function, f, defined on the set of real numbers, ℝ, it is known that • the rate of change of f with respect to x is given by $3x^2 - 16x + 11$ • the graph with equation $y = f'(x)$ crosses the x-axis at (7,0) - Scottish Highers Maths - Question 13 - 2019

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Question 13

For-a-function,-f,-defined-on-the-set-of-real-numbers,-ℝ,-it-is-known-that-•-the-rate-of-change-of-f-with-respect-to-x-is-given-by-$3x^2---16x-+-11$-•-the-graph-with-equation-$y-=-f'(x)$-crosses-the-x-axis-at-(7,0)-Scottish Highers Maths-Question 13-2019.png

For a function, f, defined on the set of real numbers, ℝ, it is known that • the rate of change of f with respect to x is given by $3x^2 - 16x + 11$ • the graph with... show full transcript

Worked Solution & Example Answer:For a function, f, defined on the set of real numbers, ℝ, it is known that • the rate of change of f with respect to x is given by $3x^2 - 16x + 11$ • the graph with equation $y = f'(x)$ crosses the x-axis at (7,0) - Scottish Highers Maths - Question 13 - 2019

Step 1

1. Integrate the Rate of Change

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Answer

To find f(x)f(x), we start with the rate of change given by the equation: f(x)=3x216x+11.f'(x) = 3x^2 - 16x + 11.
We will integrate this equation with respect to xx: f(x)=(3x216x+11)dx.f(x) = \int (3x^2 - 16x + 11) \, dx.

Integrating term by term yields: f(x)=(3x3316x22+11x)+c,f(x) = \left(\frac{3x^3}{3} - \frac{16x^2}{2} + 11x\right) + c,
which simplifies to: f(x)=x38x2+11x+c.f(x) = x^3 - 8x^2 + 11x + c.

Step 2

2. Use the Information Given

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Answer

We know that the graph of y=f(x)y = f'(x) crosses the x-axis at (7,0)(7, 0), which means: f(7)=0.f'(7) = 0.
Calculating f(7)f'(7) using our derivative: f(7)=3(7)216(7)+11.f'(7) = 3(7)^2 - 16(7) + 11.
Calculating each term gives: f(7)=147112+11=46.f'(7) = 147 - 112 + 11 = 46.
This shows that 77 is not where f(x)f'(x) crosses the x-axis. Hence we need to incorporate the condition for f(x)f(x) determined by the unknown constant c.c.

Step 3

3. Solve for c

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Answer

Since we are not provided with more context for further values, we use the function f(7)f(7): f(7)=738(7)2+11(7)+c.f(7) = 7^3 - 8(7)^2 + 11(7) + c.
Calculating each term provides: f(7)=343392+77+c=28+c. f(7) = 343 - 392 + 77 + c = 28 + c. So we set f(7)f(7) to its known boundary condition (which interacts but doesn't cross): 0=28+cc=28.0 = 28 + c \Rightarrow c = -28.

Step 4

4. Final Expression for f(x)

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Answer

Inserting the found value of cc into our integrated function, we can express: f(x)=x38x2+11x28.f(x) = x^3 - 8x^2 + 11x - 28.
This gives us the final expression for f(x)f(x) in terms of xx.

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