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Functions $f$ and $g$ are defined by • $f(x) = \frac{1}{\sqrt{x}}$, where $x > 0$ - Scottish Highers Maths - Question 12 - 2019

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Question 12

Functions-$f$-and-$g$-are-defined-by--•-$f(x)-=-\frac{1}{\sqrt{x}}$,-where-$x->-0$-Scottish Highers Maths-Question 12-2019.png

Functions $f$ and $g$ are defined by • $f(x) = \frac{1}{\sqrt{x}}$, where $x > 0$. • $g(x) = 5 - x$, where $x \in \mathbb{R}$. (a) Determine an expression for $f(... show full transcript

Worked Solution & Example Answer:Functions $f$ and $g$ are defined by • $f(x) = \frac{1}{\sqrt{x}}$, where $x > 0$ - Scottish Highers Maths - Question 12 - 2019

Step 1

Determine an expression for $f(g(x))$

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Answer

To find f(g(x))f(g(x)), we first substitute g(x)g(x) into the function ff. Given

g(x)=5x,g(x) = 5 - x,

we substitute this into ff:

f(g(x))=f(5x)=15x.f(g(x)) = f(5 - x) = \frac{1}{\sqrt{5 - x}}.

Step 2

State the range of values of $x$ for which $f(g(x))$ is undefined

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Answer

The function ff is undefined where its argument inside the square root is non-positive. Hence, we require:

5x>05 - x > 0

which simplifies to:

x<5.x < 5.

Therefore, f(g(x))f(g(x)) is undefined for all x5.x \geq 5.

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