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Question 1
PQR is a triangle with vertices P(-2, 4), Q(4, 0) and R(3, 6). Find the equation of the median through R.
Step 1
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Answer
To find the mid-point M of line segment PQ, we use the mid-point formula:
MPQ=(x1+x22,y1+y22)M_{PQ} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)MPQ=(2x1+x2,2y1+y2)
Here, P(-2, 4) and Q(4, 0).
Calculating the coordinates:
MPQ=(−2+42,4+02)=(1,2)M_{PQ} = \left( \frac{-2 + 4}{2}, \frac{4 + 0}{2} \right) = \left( 1, 2 \right)MPQ=(2−2+4,24+0)=(1,2)
Step 2
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The gradient (slope) of the median RM can be calculated using the formula:
m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}m=x2−x1y2−y1
Substituting R(3, 6) and M(1, 2):
mRM=2−61−3=−4−2=2m_{RM} = \frac{2 - 6}{1 - 3} = \frac{-4}{-2} = 2mRM=1−32−6=−2−4=2
Step 3
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To find the equation of the line for the median RM, we use the point-slope form of the equation:
y−y1=m(x−x1)y - y_1 = m(x - x_1)y−y1=m(x−x1)
Using point R(3, 6) and gradient 2:
y−6=2(x−3)y - 6 = 2(x - 3)y−6=2(x−3)
Expanding this equation gives:
y−6=2x−6y - 6 = 2x - 6y−6=2x−6
Therefore, the equation simplifies to:
y=2xy = 2xy=2x
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