A 20μF capacitor is connected to a 12V d.c - Scottish Highers Physics - Question 17 - 2017

To find the maximum charge stored on a capacitor, we use the formula:

$Q = C imes V$

where:

• $Q$ is the charge in coulombs,
• $C$ is the capacitance in farads,
• $V$ is the voltage in volts.

In this case, we have:

• $C = 20μF = 20 imes 10^{-6} F$
• $V = 12V$.

Substituting the values we get:

$Q = 20 imes 10^{-6} imes 12 = 240 imes 10^{-6} = 2.4 imes 10^{-4} C$.

Thus, the maximum charge stored on the capacitor is $2.4 × 10^3 C$, which corresponds to option B.