A circuit is set up as shown - Scottish Highers Physics - Question 22 - 2022

The charge stored on a capacitor can be calculated using the formula:

$Q = C imes V$

where:

• $Q$ is the charge in coulombs (C)
• $C$ is the capacitance in farads (F)
• $V$ is the voltage across the capacitor in volts (V)

Given:

• Capacitance, $C = 220 \, \mu F = 220 \times 10^{-6} \, F$
• Voltage, $V = 7.0 \, V$

Substituting these values into the formula gives:

$Q = 220 \times 10^{-6} \times 7 = 1.54 \times 10^{-3} \, C$

This value can be approximated as 1.5 × 10⁻³ C, which corresponds to option D.