The power dissipated in a 120Ω resistor is 4.8 W - Scottish Highers Physics - Question 16 - 2018

To find the current (I) flowing through the resistor, we use the power formula:

$P = I^2 R$

Where:

• P is the power (4.8 W)
• R is the resistance (120 Ω)

Rearranging the formula to solve for I gives us:

I = rac{ ext{P}}{R}

Substituting in the values:

I = rac{4.8 ext{ W}}{120 ext{ Ω}} = 0.04 ext{ A}