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A block of mass 6.0 kg and a block of mass 8.0 kg are connected by a string - Scottish Highers Physics - Question 3 - 2018

Question 3

A block of mass 6.0 kg and a block of mass 8.0 kg are connected by a string. A force of 32 N is applied to the blocks as shown. A frictional force of 4 N acts on ea... show full transcript

Worked Solution & Example Answer:A block of mass 6.0 kg and a block of mass 8.0 kg are connected by a string - Scottish Highers Physics - Question 3 - 2018

Step 1

Calculate the Net Force Acting on the System

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Answer

The total force applied is 32 N. The total frictional force acting on both blocks is 4 N + 4 N = 8 N.

Thus, the net force (F_net) acting on the system can be calculated as:

$F_{net} = F_{applied} - F_{friction} = 32 N - 8 N = 24 N$

Step 2

Calculate the Total Mass of the System

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Answer

The total mass (m_total) of the system is:

$m_{total} = m_{6kg} + m_{8kg} = 6 kg + 8 kg = 14 kg$

Step 3

Determine the Acceleration of the System

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Answer

Using Newton's second law, we can find the acceleration (a) of the system:

$F = m imes a$

Rearranging gives us:

$a = \frac{F_{net}}{m_{total}} = \frac{24 N}{14 kg} \approx 1.7143 m/s²$

This rounds to approximately 1.7 m/s².

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