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A box of mass m rests on a slope as shown - Scottish Highers Physics - Question 3 - 2015

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A box of mass m rests on a slope as shown. Which row in the table shows the component of the weight acting down the slope and the component of the weight acting nor... show full transcript

Worked Solution & Example Answer:A box of mass m rests on a slope as shown - Scottish Highers Physics - Question 3 - 2015

Step 1

Component of weight acting down the slope

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Answer

To find the component of the weight acting down the slope, we use the formula:

Fdown=mgimesextsin(heta)F_{down} = mg imes ext{sin}( heta)

This component acts parallel to the surface of the slope.

Step 2

Component of weight acting normal to the slope

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Answer

To find the component of the weight acting normal (perpendicular) to the slope, we use the formula:

Fnormal=mgimesextcos(heta)F_{normal} = mg imes ext{cos}( heta)

This force acts perpendicular to the surface of the slope.

Step 3

Final Answer

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Answer

Based on the calculated components, the correct row is A:

Component of weight acting down the slopeComponent of weight acting normal to the slope
mg sin(θ)mg cos(θ)

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