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A student abseils down the outside of a building using a rope - Scottish Highers Physics - Question 2 - 2019

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A student abseils down the outside of a building using a rope. The mass of the student is 55 kg. The rope, of negligible mass, is attached to a fixed point X at th... show full transcript

Worked Solution & Example Answer:A student abseils down the outside of a building using a rope - Scottish Highers Physics - Question 2 - 2019

Step 1

Calculate the weight W of the student.

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Answer

The weight W of the student can be calculated using the formula:

W=mgW = mg

Where:

  • m is the mass of the student (55 kg)
  • g is the acceleration due to gravity (approximately 9.8 m/s²)

Substituting the values:

W=55imes9.8=539extN(approximately540N)W = 55 imes 9.8 = 539 ext{ N (approximately 540 N)}

Step 2

Determine the tension T in the rope.

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Answer

To determine the tension T in the rope, we need to consider the components of forces acting on the student. The vertical component of the tension balances the weight:

W=TyW = T_y

Where:

  • Ty=Timesextcos(15°)T_y = T imes ext{cos}(15°)

From part (a), we know that W = 540 N:

540=Timesextcos(15°)540 = T imes ext{cos}(15°)

Solving for T:

T ≈ 560 ext{ N}$$

Step 3

As the student abseils down the building the angle the rope makes with the building decreases. State whether the tension in the rope increases, decreases or stays the same.

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Answer

The tension in the rope decreases as the angle decreases. This is because the cosine of the angle decreases as the angle increases, leading to a decrease in the vertical component of the tension that balances the weight. As the angle of the rope decreases, the horizontal component of the force also decreases, which results in a lower value for the tension in the rope.

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