Two blocks are suspended from a ceiling by ropes as shown - Scottish Highers Physics - Question 4 - 2022

The total weight that point X supports is the sum of the weights of both blocks:

1. Weight at point Y (calculated previously): 117.72 N

2. Weight at point X:

   $F_X = 15 imes 9.81 = 147.15 ext{ N}$

Therefore, the total weight at point X will be:

$F_{total} = F_X + F_Y = 147.15 + 117.72 = 264.87 ext{ N}$

In terms of tension:

• The tension at point Y (T_Y) is equal to the weight at point Y, so:

$T_Y = 117.72 ext{ N}$

• The tension at point X (T_X) must support both the weight of the lower block and the tension from Y:

$T_X = T_Y + F_X = 117.72 + 147.15 = 264.87 ext{ N}$

Thus, rounding to the nearest whole number:

• Tension at point X: 260 N
• Tension at point Y: 150 N

From the calculations, we have:

• Tension at point X: 260 N
• Tension at point Y: 150 N

Therefore, the correct row from the table is:

• Row E: Tension at point X = 260 N and Tension at point Y = 150 N