Photo AI

X-ray machines are used in hospitals - Scottish Highers Physics - Question 8 - 2017

Question icon

Question 8

X-ray-machines-are-used-in-hospitals-Scottish Highers Physics-Question 8-2017.png

X-ray machines are used in hospitals. An X-ray machine contains a linear accelerator that is used to accelerate electrons towards a metal target. The linear accele... show full transcript

Worked Solution & Example Answer:X-ray machines are used in hospitals - Scottish Highers Physics - Question 8 - 2017

Step 1

Calculate the work done on an electron as it accelerates from P to Q.

96%

114 rated

Answer

To calculate the work done on an electron, we can use the formula for work done by an electric field:

W=EimesQW = E imes Q

Where:

  • EE is the electric field strength and is given as 2.50 kV. We need to convert this to volts for calculations:

E=2.50imes103VE = 2.50 imes 10^3\, V

  • QQ is the charge of the electron, which is approximately 1.60imes1019C1.60 imes 10^{-19}\, C.

Substituting the values:

= 4.00 imes 10^{-16}\, J$$

Step 2

Explain why an alternating supply is used in the linear accelerator.

99%

104 rated

Answer

An alternating supply is used in the linear accelerator to ensure that the electrons are accelerated in the same direction during each cycle. This consistent acceleration is vital to maintain the focus of the electron beam towards the metal target, allowing for effective and controlled particle movement.

Step 3

Determine the direction of the magnetic field inside beam guide R.

96%

101 rated

Answer

The direction of the magnetic field inside beam guide R is out of the page.

Step 4

State two differences between the magnetic fields inside beam guides R and S.

98%

120 rated

Answer

  1. The magnetic field in guide S is stronger than that in guide R.
  2. The magnetic fields inside guides R and S are in opposite directions.

Step 5

Calculate the minimum speed of an electron that will produce a photon of energy 4 × 10^{-19} J.

97%

117 rated

Answer

To calculate the minimum speed of an electron, we can use the formula for energy:

Ek=12mv2E_k = \frac{1}{2}mv^2

Where:

  • EkE_k is the kinetic energy, which we set to 4×1019J4 \times 10^{-19}\, J,
  • mm is the mass of the electron, approximately 9.11×1031kg9.11 \times 10^{-31}\, kg.

Rearranging the formula to find v:

v=2Ekm=2×(4×1019)9.11×10319.56×106m/sv = \sqrt{\frac{2E_k}{m}} = \sqrt{\frac{2 \times (4 \times 10^{-19})}{9.11 \times 10^{-31}}} \approx 9.56 \times 10^6\, m/s

Join the Scottish Highers students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;