A stone is thrown at 50° to the horizontal with a speed of 15 m s⁻¹ - Scottish Highers Physics - Question 2 - 2019

The vertical component of the velocity can be calculated using the formula:

$V_y = V imes ext{sin}( heta)$

where:

• $V$ is the initial speed (15 m s⁻¹)
• $heta$ is the angle of projection (50°)

Thus,

$V_y = 15 imes ext{sin}(50)$

From the calculations:

• Horizontal component: $15 \times \text{cos}(50)$
• Vertical component: $15 \times \text{sin}(50)$

By comparing this to the table, row B matches these components:

• Horizontal: $15 \text{cos} 50$
• Vertical: $15 \text{sin} 50$

Therefore, the answer is Row B.