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A student carries out an experiment to verify the inverse square law for a point source of light - Scottish Highers Physics - Question 8 - 2023

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A student carries out an experiment to verify the inverse square law for a point source of light. (a) Describe an experiment to verify the inverse square law for a ... show full transcript

Worked Solution & Example Answer:A student carries out an experiment to verify the inverse square law for a point source of light - Scottish Highers Physics - Question 8 - 2023

Step 1

Describe an experiment to verify the inverse square law for a point source of light.

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Answer

To verify the inverse square law for a point source of light, set up an experiment using a light source (such as a lamp) that acts as a point source. Place a light sensor or photometer at various known distances from the light source.

  1. Apparatus: You will need a point light source, a light sensor or photometer, a ruler or measuring tape, and a stand to keep the setup stable.

  2. Method:

    • Measure the distance from the light source to the light sensor.
    • Record the readings of the light intensity (irradiance) at each distance.
    • Repeat the measurements multiple times for accuracy.
    • Plot a graph of irradiance against the distance squared.
    • According to the inverse square law, the graph should demonstrate that the irradiance is inversely proportional to the square of the distance from the light source.

Step 2

State what is meant by the term irradiance.

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Answer

Irradiance is the power per unit area incident on a surface, typically measured in watts per square meter (W/m²).

Step 3

Use all the data to establish the relationship between irradiance I and distance d.

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Answer

Using the recorded data:

  • For each distance, calculate the product of the irradiance and the square of the distance,

    • At 0.200 m: Iimesd2=142.0imes(0.200)2=5.68I imes d^2 = 142.0 imes (0.200)^2 = 5.68
    • At 0.300 m: Iimesd2=63.1imes(0.300)2=5.68I imes d^2 = 63.1 imes (0.300)^2 = 5.68
    • At 0.400 m: Iimesd2=35.5imes(0.400)2=5.68I imes d^2 = 35.5 imes (0.400)^2 = 5.68
    • At 0.500 m: Iimesd2=22.7imes(0.500)2=5.68I imes d^2 = 22.7 imes (0.500)^2 = 5.68
    • At 0.600 m: Iimesd2=15.8imes(0.600)2=5.69I imes d^2 = 15.8 imes (0.600)^2 = 5.69

This shows that the product Id2I d^2 remains approximately constant, indicating that:

d Iimesd2=constantI imes d^2 = constant Or conversely: I imes rac{1}{d^2} = constant

Step 4

Explain why the irradiance decreases when the distance from a point source of light increases.

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Answer

The irradiance decreases with increasing distance from a point source of light because as the distance increases, the same amount of light energy is spread over a larger area. According to the inverse square law, the intensity of light (irradiance) is inversely proportional to the square of the distance from the source, which means that if the distance doubles, the irradiance is reduced to a quarter of its original value. This results in a lower value of irradiance measured as you move away from the light source.

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