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The following statement represents part of a radioactive decay series - Scottish Highers Physics - Question 13 - 2022

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The following statement represents part of a radioactive decay series. $$\text{X} \xrightarrow{\alpha} \text{Y} \xrightarrow{\beta} \text{214Bi}$$ Nucleus X underg... show full transcript

Worked Solution & Example Answer:The following statement represents part of a radioactive decay series - Scottish Highers Physics - Question 13 - 2022

Step 1

Nucleus X undergoes alpha emission to produce nucleus Y.

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Answer

When nucleus X undergoes alpha emission, it loses 2 protons and 2 neutrons, resulting in a new nucleus Y that is 4 units lighter in mass and has an atomic number reduced by 2. Therefore, if we denote the mass number of nucleus X by A and its atomic number by Z, we can formulate:

AY=AX4A_Y = A_X - 4 ZY=ZX2Z_Y = Z_X - 2

To find nucleus Y, we must determine its identity based on these reductions.

Step 2

Nucleus Y then undergoes beta emission.

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In beta emission, a neutron converts into a proton, which results in an increase in atomic number by 1 while the mass number remains unchanged. Thus:

AY=AYA_Y = A_{Y'} ZY=ZY+1Z_{Y'} = Z_Y + 1

Combining the two steps, we want to identify the original nucleus X that would yield a nucleus Y producing an isotope that decays into 214Bi^{214}Bi.

Step 3

Identify Nucleus X.

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Considering the choices, we evaluate:

  • 218At^{218}At has a mass number of 218 and atomic number 85. An alpha emission results in 214Po^{214}Po (Z=84), which will beta decay to 214Bi^{214}Bi (Z=83).

Thus, nucleus X is C. 214Po^{214}Po.

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