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Retroreflective materials reflect light to enhance the visibility of clothing - Scottish Highers Physics - Question 10 - 2016

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Retroreflective materials reflect light to enhance the visibility of clothing. One type of retroreflective material is made from small glass spheres partially emb... show full transcript

Worked Solution & Example Answer:Retroreflective materials reflect light to enhance the visibility of clothing - Scottish Highers Physics - Question 10 - 2016

Step 1

Calculate the refractive index of the glass for this light.

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Answer

To calculate the refractive index (n) of the glass, we use Snell's Law, which states that
n=sinisinrn = \frac{\sin i}{\sin r}
where (i) is the angle of incidence and (r) is the angle of refraction.

From the diagram, we have (i = 36^\circ) and (r = 18^\circ).
Substituting the values:
n=sin36sin18n = \frac{\sin 36^\circ}{\sin 18^\circ}
Using a calculator, we find:
n1.9n \approx 1.9
Thus, the refractive index of the glass is approximately 1.9.

Step 2

Calculate the critical angle for this light in the glass.

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Answer

The critical angle ((\theta_c)) can be calculated using the formula: sinθc=1n\sin \theta_c = \frac{1}{n}
Substituting the value of the refractive index from part (a):
sinθc=11.9\sin \theta_c = \frac{1}{1.9}
Calculating this gives:
θc32\theta_c \approx 32^\circ
Therefore, the critical angle for the light in the glass is approximately 32 degrees.

Step 3

Complete the diagram below to show the path of the ray as it passes through the sphere and emerges into the air.

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Answer

In the completed diagram, the path of the ray will emerge into the air approximately parallel to the incident ray.
The ray will refract at the glass-air boundary as it exits the glass sphere.

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