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A person is standing at the side of a road - Scottish Highers Physics - Question 5 - 2023

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A person is standing at the side of a road. A police car approaches and then passes with a constant speed of 31 m s⁻¹. A siren on the police car emits sound with a f... show full transcript

Worked Solution & Example Answer:A person is standing at the side of a road - Scottish Highers Physics - Question 5 - 2023

Step 1

Calculate the frequency of the sound heard by the person as the police car approaches.

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Answer

To calculate the frequency of the sound heard by the person, we use the Doppler effect formula:

f=f(vvvs)f' = f \left( \frac{v}{v - v_s} \right)

Where:

  • ff' is the observed frequency.
  • ff is the source frequency (440 Hz).
  • vv is the speed of sound in air (340 m s⁻¹).
  • vsv_s is the speed of the source (31 m s⁻¹).

Substituting the values:

f=440(34034031)f' = 440 \left( \frac{340}{340 - 31} \right)

Calculating this gives:

f=440(340309)480Hz.f' = 440 \left( \frac{340}{309} \right) \approx 480 Hz.

Thus, the frequency of the sound heard by the person as the police car approaches is approximately 480 Hz.

Step 2

State whether the frequency of the sound heard by the person as the police car moves away is greater than, the same as, or less than the frequency heard by the person as the police car approached.

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Answer

The frequency of the sound heard by the person as the police car moves away is less than the frequency heard when the car was approaching. This is due to the Doppler effect where the apparent frequency decreases as the source moves away. The waves are stretched, resulting in a longer wavelength and lower frequency.

Step 3

Determine the period of the AC supply used.

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Answer

The period (T) of the AC supply can be calculated using the formula:

T=1fT = \frac{1}{f}

Given that the red and blue LEDs flash twice per second, the frequency (f) is 2 Hz. Therefore:

T=12=0.5s.T = \frac{1}{2} = 0.5 s.

Thus, the period of the AC supply used is 0.5 seconds.

Step 4

Explain why the red LEDs and the blue LEDs do not light at the same time.

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Answer

The red LEDs and blue LEDs do not light at the same time because they are connected in different configurations regarding their biasing. LED operation requires a forward bias to conduct, hence, when one color LED is forward biased, the other is reverse biased. This results in alternating light emission between the two colors at different instances.

Step 5

Determine the energy of the emitted photon.

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Answer

To determine the energy of the emitted photon, we use the equation:

E=hfE = hf

Where:

  • EE is the energy of the photon.
  • hh is Planck's constant (6.63×10346.63 \times 10^{-34} J s).
  • ff is the frequency of the photon, which can be calculated using the speed of light (cc) and wavelength (λ\lambda):

f=cλf = \frac{c}{\lambda}

Given:

  • λ=625nm=625×109m\lambda = 625 nm = 625 \times 10^{-9} m,
  • c=3.00×108m/sc = 3.00 \times 10^8 m/s,

We calculate:

f=3.00×108625×1094.8×1014Hz.f = \frac{3.00 \times 10^8}{625 \times 10^{-9}} \approx 4.8 \times 10^{14} Hz.

Now, substituting back into the energy formula:

E=(6.63×1034)(4.8×1014)3.18×1019J.E = (6.63 \times 10^{-34}) (4.8 \times 10^{14}) \approx 3.18 \times 10^{-19} J.

Therefore, the energy of the emitted photon is approximately 3.18×1019J.3.18 \times 10^{-19} J.

Step 6

Explain, in terms of the energy band gaps, the difference between the red LEDs and blue LEDs.

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Answer

The difference between the red LEDs and blue LEDs lies in their energy band gaps. Red LEDs have a larger band gap compared to blue LEDs, meaning they emit light at longer wavelengths (lower energy). In contrast, blue LEDs have a smaller band gap, allowing them to emit light at shorter wavelengths (higher energy). This inherent difference in energy gap correlates with the energy of the emitted photons, with blue light containing more energy than red light.

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