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A student uses the apparatus shown to investigate the force of friction between the wheels of a toy car and a carpet - Scottish Highers Physics - Question 2 - 2016

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A student uses the apparatus shown to investigate the force of friction between the wheels of a toy car and a carpet. The toy car is released from rest, from a heigh... show full transcript

Worked Solution & Example Answer:A student uses the apparatus shown to investigate the force of friction between the wheels of a toy car and a carpet - Scottish Highers Physics - Question 2 - 2016

Step 1

Calculate the mean distance d travelled by the car.

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Answer

To find the mean distance, we sum the distances measured and divide by the number of measurements:

d=1.31+1.40+1.38+1.41+1.355d = \frac{1.31 + 1.40 + 1.38 + 1.41 + 1.35}{5}

Calculating this gives:

d=6.855=1.37 md = \frac{6.85}{5} = 1.37 \text{ m}

Step 2

Calculate the approximate random uncertainty in this value.

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Answer

The formula for the random uncertainty (Δd) can be calculated as the range of the measurements divided by the number of measurements (n):

Δd=dmaxdminn=1.411.315=0.105=0.020 mΔd = \frac{d_{max} - d_{min}}{n} = \frac{1.41 - 1.31}{5} = \frac{0.10}{5} = 0.020 \text{ m}

Step 3

Determine which of the quantities; mass m, height h or mean distance d, has the largest percentage uncertainty.

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Answer

First, we need to calculate the percentage uncertainty for each quantity:

  1. For mass m:

    • Uncertainty: ±0.005 kg
    • Value: 0.20 kg
    • Percentage Uncertainty: %=(0.0050.20)×100=2.5%\% = \left( \frac{0.005}{0.20} \right) \times 100 = 2.5\%
  2. For height h:

    • Uncertainty: ±0.005 m
    • Value: 0.40 m
    • Percentage Uncertainty: %=(0.0050.40)×100=1.25%\% = \left( \frac{0.005}{0.40} \right) \times 100 = 1.25\%
  3. For mean distance d:

    • Uncertainty: ±0.02 m
    • Value: 1.37 m
    • Percentage Uncertainty: %=(0.021.37)×1001.46%\% = \left( \frac{0.02}{1.37} \right) \times 100 \approx 1.46\%

From these calculations, mass m has the largest percentage uncertainty.

Step 4

Calculate the potential energy of the toy car at height h.

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Answer

The potential energy (E_p) can be calculated using the formula:

Ep=mghE_p = mgh

Substituting in:

  • m = 0.20 kg
  • g = 9.81 m/s²
  • h = 0.40 m

Calculating:

Ep=0.20×9.81×0.40=0.784 JE_p = 0.20 \times 9.81 \times 0.40 = 0.784 \text{ J}

Step 5

Calculate the average force of friction acting between the toy car and carpet, as the car comes to rest.

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Answer

Using the work-energy principle, the work done by friction (W) is equal to the change in potential energy:

W=FfimesdW = F_f imes d

Since all potential energy is converted to work done against friction:

Ep=Ff×dE_p = F_f \times d

Rearranging gives:

Ff=Epd=0.7841.370.57 NF_f = \frac{E_p}{d} = \frac{0.784}{1.37} \approx 0.57 \text{ N}

Step 6

State one assumption you have made in (c)(ii).

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Answer

One assumption made could be that there is no energy or heat loss on the ramp due to friction.

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