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Language of Proof Simplified Revision Notes

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1.1.1 Language of Proof

Language of Proof

In mathematics, proof is the process of establishing the truth of a statement through logical reasoning. The language of proof is fundamental for you to know for A-Level mathematics, as it is used to validate mathematical statements rigorously.

Key Components of the Language of Proof:

  1. Statements:
  • Theorems: Proven statements that are based on established truths like axioms or other theorems.
  • Lemmas: Supporting theorems that assist in proving more significant results.
  • Corollaries: Consequences that directly follow from a theorem.
  • Conjectures: Statements believed to be true but not yet proven.
  1. Quantifiers:
  • Universal quantifier \forall: Indicates that a statement applies to all elements in a set. For example, "For all xx in the set of real numbers, x20.x^2 \geq 0 ."
  • Existential quantifier : \exists : Indicates that there is at least one element in the set for which the statement is true. For example, "There exists an integer  x\ x such that x2=4.x^2 = 4 ."
  1. Proof Techniques:
  • Proof by Deduction: Definition: Start from general principles or known facts and logically deduce the statement you want to prove.
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Example: Prove that the sum of two odd numbers is even.

  • Let a=2m+1a = 2m + 1 and b=2n+1b = 2n + 1 , where mm and nn are integers.
  • Then, (a+b=(2m+1)+(2n+1)=2(m+n+1),(a + b = (2m + 1) + (2n + 1) = 2(m + n + 1), which is even.
  • Proof by Exhaustion: Definition: Prove a statement by considering all possible cases and showing that the statement holds in each case.
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Example: Prove that a number less than 44 is either 1,2,1, 2, or 33.

  • Consider all integers less than 44: 1,2,31, 2, 3. In each case, the statement holds.
  • Proof by Counterexample: Definition: Disprove a statement by providing a specific example where the statement does not hold.
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Example: Disprove the statement "All prime numbers are odd."

  • Counterexample: 22 is a prime number and it is even, so the statement is false.
  • Proof by Contradiction: Definition: Assume the opposite of what you want to prove, and show that this assumption leads to a contradiction, thereby proving the original statement.
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Example: Prove that 2\sqrt{2} is irrational.

  • Assume 2\sqrt{2} is rational, so it can be expressed as  pq\ \frac{p}{q} in its lowest terms.
  • Then 2=p2q22 = \frac{p^2}{q^2}, implying p2=2q2p^2 = 2q^2, so pp must be even.
  • Let p=2kp = 2k, then 4k2=2q24k^2 = 2q^2 implies q2=2k2, \ q^2 = 2k^2 , so qq must also be even.
  • This contradicts the assumption that pq\frac{p}{q} is in its lowest terms, so 2\ \sqrt{2} is irrational.

Set Notation

  • Introduction:
    • When dealing with proofs, it is often the case that we need to work within specific sets of numbers.
  • Common Sets:
    • N\mathbb{N} : Set of natural numbers (all positive integers 1\geq 1)
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Example: N={1,2,3,4,}\mathbb{N} = \{ 1, 2, 3, 4, \ldots \}

  • R\mathbb{R} : Set of real numbers
  • Z\mathbb{Z} : Set of all integers (positive, negative, and zero)
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Example: Z={,3,2,1,0,1,2,3,}\mathbb{Z} = \{ \ldots, -3, -2, -1, 0, 1, 2, 3, \ldots \}

  • Q\mathbb{Q} : Set of all rational numbers
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Definition: Q={ab:a,bZ}\mathbb{Q} = \left\{ \frac{a}{b} : a, b \in \mathbb{Z} \right\} aa and bb are integers

  • C\mathbb{C} : Set of complex numbers
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Definition: C={a+bi:a,bR}\mathbb{C} = \{ a + bi : a, b \in \mathbb{R} \}

Definition of a Set:

  • AA set is a "bag" containing "things".
  • Curved points (braces) indicate a set: {}\{\}
  • No repeated items in sets. For example, {1, 2, 3} is correct, not {1, 2, 2, 3}.

Notation:

  • {}\{\} : A set.
  • \in : "is a member of".
  • \emptyset or {}\{\} : An empty set.
  • \cup : Union of two sets, combining elements and removing repetitions.
  • \cap : Intersection of two sets, elements they have in common.
  • \complement : The complement of a set, all items that are not in the set.

Common Sets:

  • N\mathbb{N}: Natural numbers {1,2,3,}\{ 1, 2, 3, \ldots \}.
  • Z\mathbb{Z} : Integers {,3,2,1,0,1,2,3,} \{ \ldots, -3, -2, -1, 0, 1, 2, 3, \ldots \}.
  • N0\mathbb{N}_0 : Natural numbers including 00.
  • R\mathbb{R} : Real numbers.
  • Q\mathbb{Q} : Rational numbers {ab:a,bZ,}\left\{ \frac{a}{b} : a, b \in \mathbb{Z}, \right\}. Note: ab\frac{a}{b} means "such that" a and b are integers.
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Examples:

  1. List all numbers that are members of the following sets:
  • a) {xx4,xN}\{ x \mid x \leq 4, x \in \mathbb{N} \}
  • (x)( x ) is less than or equal to 44, (xx ) is a natural number.
  • Answer: {1,2,3,4}\{ 1, 2, 3, 4 \}
  • b) {x:x4,xN}{p:p is prime}\{ x : x \leq 4, x \in \mathbb{N} \} \cap \{ p : p \text{ is prime} \}
  • Find where the two sets overlap.
  • {1,2,3,4}{2,3,5,7,11,13,}\{ 1, 2, 3, 4 \} \cap \{ 2, 3, 5, 7, 11, 13, \ldots \}
  • Answer: {2,3}\{ 2, 3 \}
  • c) {x:x4,xN}{2n:nN}\{ x : x \leq 4, x \in \mathbb{N} \} \cap \{ 2n : n \in \mathbb{N} \}
  • Even numbers in N\mathbb{N} less than or equal to 44.
  • {1,2,3,4}{2,4,6,8,}\{ 1, 2, 3, 4 \} \cap \{ 2, 4, 6, 8, \ldots \}
  • Answer: {2,4}\{ 2, 4 \}

Interval Notation

  • Purpose: Convenient way of expressing inequalities.
  • Symbols:
    • Square brackets: Means "can be equal to."
    • Round brackets: Means "cannot equal."
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Example 1:

  • [6,12][6, 12] : All real numbers between 66 and 1212 inclusive.

  • Equivalent set notation: {x:xR,6x12}\{ x : x \in \mathbb{R}, 6 \leq x \leq 12 \} Example 2:

  • [7,14][7, 14] : All real numbers between 77 and 1414, 77 not included, 1414 included.

  • Equivalent set notation: {x:7<x14,xR}\{ x : 7 < x \leq 14, x \in \mathbb{R} \}

Incorrect Intervals:

infoNote

Example 3:

  • (12,8)(12, 8)
  • Issue: Numbers in the wrong order.
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Example 4:

  • (7,)(7, \infty)
  • Issue: Nothing can equal infinity.

Past Exam Question:

June 2018, Paper 1, Question 8: "Prove by exhaustion that the function f(x)=x2x+2f(x) = x^2 - x + 2 is always positive for integer values of xx in the set {0,1,2}\{0, 1, 2\}."

Solution Outline:

  • Statement: Evaluate f(x)=x2x+2f(x) = x^2 - x + 2 for each value of xx in the set {0,1,2}.\{0, 1, 2\} .
    • For (x=0), f(0)=020+2=:success[2].( x = 0 ), \ f(0) = 0^2 - 0 + 2 = :success[2] .
    • For (x=1), f(1)=121+2=:success[2].( x = 1 ), \ f(1) = 1^2 - 1 + 2 = :success[2] .
    • For (x=2), f(2)=222+2=:success[4]( x = 2 ), \ f(2) = 2^2 - 2 + 2 = :success[4] .
  • Conclusion: Since f(x)f(x) is positive for all values of  x\ x in the set  {0,1,2},\ \{0, 1, 2\} , the function is always positive. This example demonstrates proof by exhaustion, where all possible cases are checked individually to establish the truth of the statement.

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