Strategy for Trigonometric Equations Simplified Revision Notes for A-Level AQA Maths Pure
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Learn about Trigonometric Equations for your A-Level Maths Pure Exam. This Revision Note includes a summary of Trigonometric Equations for easy recall in your Maths Pure exam
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5.3.4 Strategy for Trigonometric Equations
Solving trigonometric equations can be challenging, but with a systematic approach, you can tackle them efficiently. Here's a general strategy to help you solve a wide range of trigonometric equations:
1.Understand the Equation
Identify which trigonometric function(s) are involved (e.g., sinθ,cosθ,tanθ).
Determine whether the equation is linear (e.g.,sinθ=21), quadratic (e.g., 2sin2θ−sinθ−1=0), or involves multiple trigonometric functions.
2.Simplify the Equation
Isolate the trigonometric function: Get the trigonometric function (e.g.,sinθ,cosθ) by itself on one side of the equation.
Factor or Simplify: If the equation is quadratic or more complex, try factoring, expanding, or simplifying using trigonometric identities.
Substitution: If multiple trigonometric functions are involved (e.g., sin2θ+cos2θ=1), consider substituting using identities to reduce the equation to one trigonometric function.
3.Use Trigonometric Identities
Apply identities such as the Pythagorean identities, double-angle identities, sum-to-product identities, or half-angle identities to simplify the equation.
Common identities include:
sin2θ+cos2θ=1tanθ=cosθsinθsin(2θ)=2sinθcosθ
4.Solve the Simplified Equation
Linear Equations:
Solve for the angle by taking the inverse trigonometric function (e.g.,sin−1,cos−1,tan−1).
Consider all solutions within the given interval by accounting for the periodic nature of the trigonometric functions.
Quadratic Equations:
Factor if possible, or use the quadratic formula:
u=2a−b±b2−4ac
Back-substitute to solve for the angle.
Check for extraneous solutions, especially if you square both sides of the equation.
5.Consider the General Solution
Trigonometric functions are periodic, meaning they repeat their values at regular intervals.
For sinθ=kandcosθ=k:
θ=θ0+360∘n(or2π n) where n is any integer.
Include both primary solutions θ0and180∘−θ0(orπ−θ0).
For tanθ=k:
θ=θ0+180∘n(orπn).
6.List All Solutions in the Given Interval
Ensure that all solutions are within the specified interval, typically 0∘to360∘ or 0to2π radians.
Adjust the general solution accordingly to fit within this range.
7.Verify Solutions
Substitute each solution back into the original equation to ensure it satisfies the equation.
Discard any extraneous solutions that might have arisen from squaring both sides or other manipulations.
infoNote
Example Strategy Application:
Problem: Solve 2sin2θ−3sinθ+1=0for0∘≤θ≤360∘.
Identify: This is a quadratic trigonometric equation in sinθ.
Substitute: Let u =sinθ, so the equation becomes 2u2−3u+1=0.
Factor: Factor the quadratic:
(2u−1)(u−1)=0
So, u = 21oru=1.
Back-substitute: Replace u with sinθ:
sinθ=21
sinθ=1
Solve:
For sinθ=21:θ=30∘,150∘
For sinθ=1:θ=90∘
List All Solutions: The solutions in the interval 0∘≤θ≤360∘ are:
θ=30∘,90∘,150∘
Verify: Substitute these angles back into the original equation to ensure they are correct.
Summary:
Simplify the trigonometric equation using identities or substitution.
Solve the resulting equation for the variable.
Consider the periodic nature of trigonometric functions to find all solutions within the given interval.
Verify the solutions to ensure correctness.
Solving Trig Equations Involving Compound Angles
By "compound angle," we mean "an angle more complicated than just θ."
infoNote
Example: Solve sin(3θ)=0.42,0≤θ≤180.
Notice we are solving for θ, but the angle is 3θ within the sin function.
0≤3θ≤540(×3)
Modify the domain to find limits for the compound angle in the bracket.
Find all solutions for our compound angle (in this case, it's3θ)
3θ=arcsin(0.42)≈24.85∘
Calculator Steps:
Press [ sin−1 ] then the letters to recall this number.
Store long numbers by pressing [STO] then a letter with a red letter.
Findθfor each intermediate solution (in this case, divide all by3):
θ=:success[8.278∘,51.72∘,128.3∘,171.7∘](4sf)
infoNote
Example: Solve cos(x−37.6∘)=0.17,0≤x≤540.
x=:success[137.4∘,297.8∘,497.4∘](4sf)
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