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Basics of electricity Simplified Revision Notes

Revision notes with simplified explanations to understand Basics of electricity quickly and effectively.

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5.1.1 Basics of electricity

Key Concepts of Electricity

  1. Electric Current (II)
  • Definition: Electric current is the flow of charge per unit time, essentially describing the rate at which charge moves through a conductor.
  • Formula:
I=ΔQΔtI = \frac{\Delta Q}{\Delta t}

Where:

  • II = current (measured in amperes, AA),
  • ΔQ\Delta Q = charge passing through a point (measured in coulombs, C),
  • Δt\Delta t = time taken for the charge to pass (measured in seconds, ss).
  • Explanation: Current is the amount of electric charge flowing past a point per second. Higher current means more charge is passing each second.
  1. Potential Difference (VV)
  • Definition: Potential difference (often called voltage) is the energy transferred per unit charge between two points in a circuit. It represents the work done to move a charge from one point to another.
  • Formula:
V=WQV = \frac{W}{Q}

Where:

  • VV = potential difference (measured in volts, VV),
  • WW = energy transferred (measured in joules, JJ),
  • QQ = charge (measured in coulombs, CC).
  • Explanation: Voltage can be thought of as the "push" provided to charges, helping them move through the circuit. A higher potential difference means more energy is provided to each coulomb of charge.
  1. Resistance (R)
  • Definition: Resistance is a measure of how much a component in a circuit opposes the flow of charge. It indicates how difficult it is for current to pass through a material.
  • Formula:
R=VIR = \frac{V}{I}

Where:

  • RR = resistance (measured in ohms, Ω\Omega ),
  • VV = potential difference across the component (volts, VV),
  • II = current through the component (amperes, AA).
  • Explanation: Resistance affects the current for a given potential difference. Components with higher resistance allow less current to pass for the same voltage.
infoNote

Worked Example

Example Problem: A current of 22 A flows through a resistor with a potential difference of 1010 VV across it. Find the resistance of the resistor.

  1. Given:
  • Current I=2 AI = 2 \, \text{A}
  • Potential difference V=10 VV = 10 \, \text{V}
  1. Formula: R=VIR = \frac{V}{I}
  2. Calculation:
R=102=5 ΩR = \frac{10}{2} = 5 \, \Omega

Answer: The resistance of the resistor is 5 Ω5 \, \Omega.

infoNote

Key Points

  • Electric Current: Flow of charge per second, measured in amperes (AA).
  • Potential Difference (Voltage): Energy transferred per unit charge, measured in volts (VV).
  • Resistance: Opposes current, calculated as the ratio of potential difference to current, measured in ohms Ω \Omega.
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