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Introduction to Complex Numbers Simplified Revision Notes

Revision notes with simplified explanations to understand Introduction to Complex Numbers quickly and effectively.

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1.1.1 Introduction to Complex Numbers

Overview

A complex number is any number that can be written in the form:

z=a+biz = a + bi

where:

  • aa is the real part (Re(z)=a)(\text{Re}(z) = a)
  • bb is the imaginary part (Im(z)=b)(\text{Im}(z) = b)
  • ii is the imaginary unit, defined by i2=1i^2 = -1
lightbulbExample

Example: For the complex number z=3+4iz = 3 + 4i

  • Real part = 33
  • Imaginary part = 44

Basic Operations on Complex Numbers

Addition

To add two complex numbers, add their real and imaginary parts separately.

(a+bi)+(c+di)=(a+c)+(b+d)i(a + bi) + (c + di) = (a + c) + (b + d)i
lightbulbExample

Example:

(2+3i)+(1+4i)(2 + 3i) + (1 + 4i)
=(2+1)+(3+4)i= (2 + 1) + (3 + 4)i =3+7i= 3 + 7i

Subtraction

To subtract two complex numbers, subtract their real and imaginary parts separately.

(a+bi)(c+di)=(ac)+(bd)i(a + bi) - (c + di) = (a - c) + (b - d)i
lightbulbExample

Example:

(5+2i)(3+6i)(5 + 2i) - (3 + 6i)
=(53)+(26)i= (5 - 3) + (2 - 6)i=24i= 2 - 4i

Multiplication

To multiply two complex numbers, expand using the distributive property and simplify using:

i2=1i^2 = -1

(a+bi)(c+di)=ac+adi+bci+bdi2=(acbd)+(ad+bc)i(a + bi)(c + di) = ac + adi + bci + bdi^2 = (ac - bd) + (ad + bc)i
lightbulbExample

Example:

(3+2i)(1+4i)(3 + 2i)(1 + 4i)

Step 1**:** Expand using distributive property:

=3(1)+3(4i)+2i(1)+2i(4i)= 3(1) + 3(4i) + 2i(1) + 2i(4i)

Step 2: Simplify:

=3+12i+2i+8i2=3+14i8=5+14i= 3 + 12i + 2i + 8i^2 = 3 + 14i - 8 = -5 + 14i
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Example:

(3+4i)(5+6i)(3 + 4i)(-5 + 6i)

Step 1: Expand:

=3(5)+3(6i)+4i(5)+4i(6i)= 3(-5) + 3(6i) + 4i(-5) + 4i(6i)

Step 2: Simplify:

=15+18i20i+24i2= -15 + 18i - 20i + 24i^2 =152i24= -15 - 2i - 24 =392i= -39 - 2i

Division

To divide two complex numbers, multiply both the numerator and denominator by the conjugate of the denominator.

Conjugate of a+bia + bi is abia - bi

Formula:

a+bic+di=(a+bi)(cdi)(c+di)(cdi)\frac{a + bi}{c + di} = \frac{(a + bi)(c - di)}{(c + di)(c - di)}
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Example:

2i4+3i\frac{2 - i}{4 + 3i}

Step 1: Multiply by the conjugate 43i4 - 3i

=(2i)(43i)(4+3i)(43i)= \frac{(2 - i)(4 - 3i)}{(4 + 3i)(4 - 3i)}

Step 2: Expand numerator:

=(2i)(43i)= (2 - i)(4 - 3i) =86i4i+3i2= 8 - 6i - 4i + 3i^2 =510i= 5 - 10i

Step 3: Expand denominator:

=(4+3i)(43i)= (4 + 3i)(4 - 3i) =169i2= 16 - 9i^2 =25= 25

Step 4: Simplify:

=510i25= \frac{5 - 10i}{25} =1525i= \frac{1}{5} - \frac{2}{5}i
infoNote

Additional Example: Simplify

3+2i4+5i\frac{3 + 2i}{4 + 5i}

Step 1: Multiply by conjugate 45i4 - 5i

=(3+2i)(45i)(4+5i)(45i)= \frac{(3 + 2i)(4 - 5i)}{(4 + 5i)(4 - 5i)}

Step 2: Expand numerator:

=1215i+8i10i2= 12 - 15i + 8i - 10i^2 =227i= 22 - 7i

Step 3: Expand denominator:

=1625i2= 16 - 25i^2 =41= 41

Step 4: Simplify:

=227i41= \frac{22 - 7i}{41} =2241741i= \frac{22}{41} - \frac{7}{41}i

Worked Examples

lightbulbExample

Example 1: Simplify (2+3i)(4i)(2 + 3i)(4 - i)


Step 1: Expand:

=(2+3i)(4i)= (2 + 3i)(4 - i) =2(4)+2(i)+3i(4)+3i(i)= 2(4) + 2(-i) + 3i(4) + 3i(-i)

Step 2: Simplify:

=82i+12i3i2= 8 - 2i + 12i - 3i^2

Step 3: Combine like terms:

=8+10i+3= 8 + 10i + 3 =11+10i= 11 + 10i
lightbulbExample

Example 2: Simplify 1+2i3+4i\frac{1 + 2i}{3 + 4i}


Step 1: Multiply by the conjugate 34i3 - 4i

(1+2i)(34i)(3+4i)(34i)\frac{(1 + 2i)(3 - 4i)}{(3 + 4i)(3 - 4i)}

Step 2: Expand numerator:

=(1+2i)(34i)= (1 + 2i)(3 - 4i) =34i+6i8i2= 3 - 4i + 6i - 8i^2 =3+2i+8= 3 + 2i + 8 =11+2i= 11 + 2i

Step 3: Expand denominator:

=(3+4i)(34i)= (3 + 4i)(3 - 4i) =9+16=25= 9 + 16 = 25

Step 4: Simplify:

=11+2i25= \frac{11 + 2i}{25} =1125+225i= \frac{11}{25} + \frac{2}{25}i
lightbulbExample

Example 3: Solve z22z+17=0z^2 - 2z + 17 = 0 by completing the square


Step 1: Rewrite:

z22z=17z^2 - 2z = -17

Step 2: Complete the square:

(z1)21=17(z - 1)^2 - 1 = -17 \quad (z1)2=16\Rightarrow \quad (z - 1)^2 = -16

Step 3: Solve:

z1=±4iz - 1 = \pm 4i \quad z=1±4i\Rightarrow \quad z = 1 \pm 4i

Note Summary

infoNote

Common Mistakes:

  1. Forgetting i2=1i^2 = -1 when simplifying terms.
  2. Incorrectly applying the conjugate in division.
  3. Mixing up real and imaginary parts during addition or subtraction.
  4. Expanding incorrectly in multiplication.
  5. Skipping simplification steps leads to wrong final answers.
infoNote

Key Formulas:

  1. Addition**:** (a+bi)+(c+di)=(a+c)+(b+d)i(a+bi) + (c+di) = (a+c) + (b+d)i
  2. Subtraction**:** (a+bi)(c+di)=(ac)+(bd)i(a+bi) - (c+di) = (a-c) + (b-d)i
  3. Multiplication: (a+bi)(c+di)=(acbd)+(ad+bc)i(a+bi)(c+di) = (ac - bd) + (ad + bc)i
  4. Division: a+bic+di=(a+bi)(cdi)c2+d2\frac{a+bi}{c+di} = \frac{(a+bi)(c-di)}{c^2+d^2}
  5. Conjugate**:** a+bi=abi\overline{a+bi} = a - bi
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