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Change of Sign Simplified Revision Notes

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10.1.1 Change of Sign

Numerical Methods for Solving Equations

In A Level Maths, the change of sign method is used to find the roots of an equation f(x)=0f(x) = 0 by identifying where the function changes from positive to negative (or vice versa).

Step-by-step process:

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  1. Identify intervals: Look for an interval [a,b][a, b] where f(a)f(a) and f(b) f(b) have opposite signs (i.e., one is positive and the other is negative).
  2. Narrow the interval: Use methods like decimal search or interval bisection to find a smaller interval where a change of sign occurs.
  3. Root approximation: The root lies in the interval where the change of sign occurs. This method works well when the function is continuous and the root isn't repeated. It provides an approximate solution to equations that are difficult to solve algebraically.

Locating Roots via Change of Sign

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Example: Show that the equation x2+7x12=0x^2 + 7x - 12 = 0 has a root between x=1x = 1 and x=2x = 2. Theory: Graphically, a function has a root when its graph crosses the xx-axis. If it is above the axis before it crosses, it will be below the xx-axis after it crosses.

Function: f(x)=x2+7x12f(x) = x^2 + 7x - 12

  1. Substitute the boundaries of the interval in which the root is thought to lie and compare the results to 0:
f(1)=(1)2+7(1)12=4(<0)f(1) = (1)^2 + 7(1) - 12 = -4 \quad (< 0)f(2)=(2)2+7(2)12=6(>0)f(2) = (2)^2 + 7(2) - 12 = 6 \quad (> 0)
  1. Write the following conclusion:
  • Change of sign: Since the function is continuous in the interval [1,2][1, 2], a root must be present.
  • The root lies in the interval [1,2][1, 2].

Proving a Root Correct to 3 Decimal Places

Given Function: f(x)=3+x2x3f(x) = 3 + x^2 - x^3

Objective: Prove that x=1.864x = 1.864 is a root correct to 3 decimal places.

  1. Identify the Interval:
  • To prove that x=1.864x = 1.864 is correct to 3 decimal places, we need to show that any value that rounds to 1.8641.864 lies within an interval containing the root.
  • Since we're rounding to 3dp, xx must lie within the interval [1.8635,1.8645][1.8635, 1.8645].
  1. Check the Function Values at the Interval Boundaries:
  • Calculate f(1.8635) and f(1.8645)f(1.8635)\ and\ f(1.8645):
  • f(1.8635)=1.98×103>0f(1.8635) = 1.98 \times 10^{-3} > 0
  • f(1.8645)=5.13×103<0f(1.8645) = -5.13 \times 10^{-3} < 0
  • Notice the change of sign between these two values.
  1. Conclusion:
  • The change of sign and the continuity of the function within the interval [1.8635,1.8645][1.8635, 1.8645] indicate that the root lies within this interval.
  • Therefore, x=1.864x = 1.864 is indeed a root correct to 3dp.

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