Calculating Enthalpy Changes Simplified Revision Notes for Scottish Highers Chemistry
Revision notes with simplified explanations to understand Calculating Enthalpy Changes quickly and effectively.
Learn about Enthalpy for your Scottish Highers Chemistry Exam. This Revision Note includes a summary of Enthalpy for easy recall in your Chemistry exam
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Calculating Enthalpy Change
Introduction:
Enthalpy change (ΔH) is a fundamental concept in chemistry used to quantify the energy changes in chemical reactions.
ΔH can be calculated using the equation: ΔH = mcΔT, where ΔH is in kJ or kJ mol⁻¹, m is the mass of water (in kg), c is the specific heat capacity of water (a constant, 4.18 kJ kg⁻¹°C⁻¹), and ΔT is the change in temperature (°C).
Example Calculation
Question: A solution was made by dissolving a spatula of potassium nitrate into 50 cm3 of water. The temperature changed from 20.4°C to 18.7°C. Calculate the enthalpy change for this reaction.
To calculate ΔH, we need values for c, m, and ΔT.
Specific heat capacity (c) is a constant (4.18 kJ kg⁻¹°C⁻¹).
The mass of water (m) is 0.05 kg (since 50 cm3 = 0.05 kg).
ΔT is 1.7°C (temperature decrease, indicating an endothermic reaction).
Calculation
ΔH = mcΔT
ΔH = 4.18 x 0.05 x 1.7
ΔH = 0.3553 kJ
Combustion Calculations
Combustion calculations involve the enthalpy change associated with the burning of a substance.
Enthalpy of combustion (ΔHc) measures the energy released when one mole of a substance burns completely in oxygen.
The balanced equations for enthalpies of combustion should include one mole of the substance.
Calculating Enthalpy Change
Worked Example 1
Given: When 1g of ethanol is burned, 30 kJ of energy is released.
Calculate the Enthalpy of Combustion for ethanol.
Calculation: 1g → 30 kJ, GFM 46g → X kJ
X kJ x 1g = 30 kJ x 46g
X kJ = 30 kJ x 46g / 1g
X kJ = 1380 kJ
Enthalpy of Combustion for ethanol = -1380 kJ mol⁻¹
Worked Example 2
Given: 0.16g of methanol (CH₃OH) is burned, raising the temperature of 100g of water from 20°C to 27°C.
Calculate the enthalpy of combustion of methanol.
Calculation: ΔH = mcΔT
ΔH = 4.18 x 0.1 kg x 7°C
ΔH = 2.926 kJ
0.16g → 2.926 kJ, 32g → X kJ
X = 2.926 kJ x 32 / 0.16
X = 585.2 kJ
Enthalpy of Combustion of methanol = -585.2 kJ mol⁻¹
Conclusion:
Enthalpy change (ΔH) can be calculated using the formula ΔH = mcΔT.
Enthalpy of combustion (ΔHc) measures the energy released when one mole of a substance burns completely in oxygen.
These calculations help chemists understand the energy changes in chemical reactions.
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