Example-Conservation of Kinetic Energy Simplified Revision Notes for Scottish Highers Physics
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Learn about Collisions, Explosions and Impulse for your Scottish Highers Physics Exam. This Revision Note includes a summary of Collisions, Explosions and Impulse for easy recall in your Physics exam
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Conservation of Kinetic Energy Example
Scenario
A red snooker ball and a blue snooker ball, each with a mass of 160 g, are involved in a collision.
The red ball is initially moving from left to right at 0.28 m/s, while the blue ball is moving from right to left at 0.12 m/s.
After the collision, the blue ball moves from left to right at 0.18 m/s.
Calculate the velocity of the red ball after the collision.
Total momentum before the collision is equal to the total momentum after the collision.
Using the formula for momentum (p = mv), we have:
Total initial momentum = Total final momentum
(0.160 kg Ă— 0.28 m/s) + (0.160 kg Ă— (-0.12 m/s)) = (0.160 kg Ă— V)
(0.0448 kg m/s) - (0.0192 kg m/s) = (0.160 kg Ă— V)
(0.0256 kg m/s) = (0.160 kg Ă— V)
V = (0.0256 kg m/s) / (0.160 kg)
V = -0.16 m/s
The velocity of the red ball after the collision is approximately -0.16 m/s. The negative sign indicates that the direction is from right to left.
Use kinetic energy to determine whether the collision was elastic
To determine if the collision is elastic or not, we need to calculate the kinetic energy before and after the collision.
The equation for kinetic energy is KE = ½mv², where KE is kinetic energy, m is mass, and v is velocity.
Kinetic Energy Before the Collision
For the red ball: KE_red = ½ × 0.160 kg × (0.28 m/s)² = 0.006272 J
For the blue ball: KE_blue = ½ × 0.160 kg × (-0.12 m/s)² = 0.0009216 J
Total kinetic energy before the collision: KE_initial = KE_red + KE_blue = 0.006272 J + 0.0009216 J = 0.0071936 J
Conservation of Kinetic Energy Example
Kinetic Energy After the Collision
For the red ball (with velocity -0.16 m/s): KE_red_after = ½ × 0.160 kg × (-0.16 m/s)² = 0.002048 J
For the blue ball (with velocity 0.18 m/s): KE_blue_after = ½ × 0.160 kg × (0.18 m/s)² = 0.002304 J
Total kinetic energy after the collision: KE_final = KE_red_after + KE_blue_after = 0.002048 J + 0.002304 J = 0.004352 J
Comparison of Kinetic Energies
Total kinetic energy lost during the collision: ΔKE = KE_initial - KE_final = 0.0071936 J - 0.004352 J = 0.0028416 J
The collision is inelastic because kinetic energy is not conserved. In this case, 0.0028416 J of energy is lost during the collision.
Summary
The velocity of the red ball after the collision is approximately -0.16 m/s.
The collision is determined to be inelastic because there is a loss of kinetic energy, with 0.0028416 J of energy being lost during the collision.
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