In which of the following reactions does the metal atom show the greatest change in oxidation state?
(A) MnO₄⁻ to Mn²⁺
(B) MnO₂ to Mn(OH)₃
(C) PbO₂ to PbSO₄
(D) VO₂⁻ to VO²⁺ - HSC - SSCE Chemistry - Question 12 - 2010 - Paper 1
Question 12
In which of the following reactions does the metal atom show the greatest change in oxidation state?
(A) MnO₄⁻ to Mn²⁺
(B) MnO₂ to Mn(OH)₃
(C) PbO₂ to PbSO₄
(D) VO₂... show full transcript
Worked Solution & Example Answer:In which of the following reactions does the metal atom show the greatest change in oxidation state?
(A) MnO₄⁻ to Mn²⁺
(B) MnO₂ to Mn(OH)₃
(C) PbO₂ to PbSO₄
(D) VO₂⁻ to VO²⁺ - HSC - SSCE Chemistry - Question 12 - 2010 - Paper 1
Step 1
Calculate the change in oxidation state for (A) MnO₄⁻ to Mn²⁺
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Answer
Manganese (Mn) in MnO₄⁻ has an oxidation state of +7. When it is reduced to Mn²⁺, the oxidation state changes to +2. This results in a change of:
+7−(+2)=+5
Step 2
Calculate the change in oxidation state for (B) MnO₂ to Mn(OH)₃
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Answer
In MnO₂, Mn has an oxidation state of +4. In Mn(OH)₃, the oxidation state of Mn is still +3. This results in a change of:
+4−(+3)=+1
Step 3
Calculate the change in oxidation state for (C) PbO₂ to PbSO₄
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Answer
Lead (Pb) in PbO₂ has an oxidation state of +4. In PbSO₄, the oxidation state of Pb remains +2. This results in a change of:
+4−(+2)=+2
Step 4
Calculate the change in oxidation state for (D) VO₂⁻ to VO²⁺
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Answer
In VO₂⁻, Vanadium (V) has an oxidation state of +5. In VO²⁺, the oxidation state of V is +4. This results in a change of:
+5−(+4)=+1
Step 5
Determine the greatest change in oxidation state
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Answer
From the calculations above, the oxidation state changes are as follows:
(A) +5
(B) +1
(C) +2
(D) +1
The greatest change in oxidation state occurs in option (A) MnO₄⁻ to Mn²⁺, with a change of +5.
