This question is about making a diester from cyclohexanol. Step 1 Step 2 Step 3 Step 4 --- 08.1 State the type of reaction in step 1. Give the name of the reagent needed for step 1. Type of reaction ___________ Reagent ___________ 08.2 State the reagents needed and give equations for step 2 and step 3. Show the structure of Compound G in your equations. Step 2 reagent ___________ Step 2 equation ___________ Step 3 reagent ___________ Step 3 equation ___________ 08.3 Cyclohexane-1,2-diol reacts with ethanedioyl dichloride. Give the name of the mechanism for this reaction. Complete the mechanism to show the formation of one ester link in the first step of this reaction. Mechanism name ___________ Mechanism ___________ 08.4 Suggest why chemists usually aim to design production methods • with fewer steps • with a high percentage atom economy. Fewer steps ___________ High percentage atom economy ___________

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This question is about making a diester from cyclohexanol - AQA - A-Level Chemistry - Question 8 - 2021 - Paper 2

Question 8

This question is about making a diester from cyclohexanol. Step 1 Step 2 Step 3 Step 4 --- 08.1 State the type of reaction in step 1. Give the name of the reag... show full transcript

Worked Solution & Example Answer:This question is about making a diester from cyclohexanol - AQA - A-Level Chemistry - Question 8 - 2021 - Paper 2

Step 1

State the type of reaction in step 1.

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Answer

The type of reaction in step 1 is dehydration, specifically an elimination reaction where water is removed from cyclohexanol.

Step 2

Give the name of the reagent needed for step 1.

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Answer

The reagent needed for step 1 is concentrated sulfuric acid (H₂SO₄).

Step 3

State the reagents needed and give equations for step 2 and step 3.

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Answer

For step 2, the reagent needed is sodium hydroxide (NaOH). The equation for step 2 is:

$ext{Cyclohexene + NaOH} \rightarrow ext{product}$

For step 3, the reagent needed is ethanedioyl dichloride (ClCOCOCl). The equation for step 3 is:

$ext{Cyclohexane-1,2-diol + ClCOCOCl} \rightarrow ext{diester}$

Step 4

Give the name of the mechanism for this reaction.

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Answer

The mechanism for this reaction is nucleophilic addition-elimination.

Step 5

Complete the mechanism to show the formation of one ester link in the first step of this reaction.

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Answer

The mechanism involves the nucleophilic attack of the hydroxyl (-OH) group of cyclohexane-1,2-diol on the carbonyl carbon of ethanedioyl dichloride that leads to the formation of a tetrahedral intermediate, followed by elimination of HCl to form one ester link.

Step 6

Suggest why chemists usually aim to design production methods with fewer steps.

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Answer

Fewer steps in production methods are preferred because they reduce production time and costs, leading to higher efficiency in manufacturing processes.

Step 7

Suggest why chemists usually aim to design production methods with a high percentage atom economy.

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Answer

A high percentage atom economy is desirable as it minimizes waste and maximizes the use of reactants, thus making the process more sustainable and environmentally friendly.

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This question is about making a diester from cyclohexanol - AQA - A-Level Chemistry - Question 8 - 2021 - Paper 2

Worked Solution & Example Answer:This question is about making a diester from cyclohexanol - AQA - A-Level Chemistry - Question 8 - 2021 - Paper 2

State the type of reaction in step 1.

Give the name of the reagent needed for step 1.

State the reagents needed and give equations for step 2 and step 3.

Give the name of the mechanism for this reaction.

Complete the mechanism to show the formation of one ester link in the first step of this reaction.

Suggest why chemists usually aim to design production methods with fewer steps.

Suggest why chemists usually aim to design production methods with a high percentage atom economy.

Join the A-Level students using SimpleStudy...

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