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Figure 1 shows part of the curve with equation $y = e^{0.5x}$ - Edexcel - A-Level Maths: Pure - Question 4 - 2008 - Paper 7

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Figure 1 shows part of the curve with equation $y = e^{0.5x}$. The finite region $R$, shown shaded in Figure 1, is bounded by the curve, the x-axis, the y-axis and t... show full transcript

Worked Solution & Example Answer:Figure 1 shows part of the curve with equation $y = e^{0.5x}$ - Edexcel - A-Level Maths: Pure - Question 4 - 2008 - Paper 7

Step 1

Complete the table with the values of $y$ corresponding to $x = 0.8$ and $x = 1.6$

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Answer

To find the values for yy when x=0.8x = 0.8 and x=1.6x = 1.6, we can use the equation y=e0.5xy = e^{0.5x}:

For x=0.8x = 0.8: y=e0.5imes0.8=e0.4≈1.49182y = e^{0.5 imes 0.8} = e^{0.4} \\ \approx 1.49182 (rounded to 5 significant figures)

For x=1.6x = 1.6: y=e0.5imes1.6=e0.8≈2.22554y = e^{0.5 imes 1.6} = e^{0.8} \\ \approx 2.22554 (rounded to 5 significant figures)

Thus, the completed table with approximate values is:

xx00.40.81.21.62
yy1.01.01.491821.491821.648721.648722.225542.225543.680783.680787.389067.38906

Step 2

Use the trapezium rule with all the values in the table to find an approximate value for the area of $R$

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Answer

To apply the trapezium rule, we need to calculate the area using the formula: A = rac{1}{2}ht(a+b) + h \\sum_{i=1}^{n-1}y_i where AA is the area, hh is the width of the trapezium, aa and bb are the heights of the first and last sections respectively, and yiy_i are the intermediate heights.

  1. Width of each sub-interval (h):

    • The interval is [0,2][0, 2], thus h=0.4h = 0.4.
    • The values of yy from the table are approximately: 1.0,1.49182,1.64872,2.22554,3.68078,7.389061.0, 1.49182, 1.64872, 2.22554, 3.68078, 7.38906
  2. Using the trapezium rule:

    • Area: A = rac{1}{2} (0.4) (1.0 + 7.38906) + 0.4 (1.49182 + 1.64872 + 2.22554 + 3.68078)
    • Calculating the sums: =0.2(8.38906)+0.4(9.04686)=1.677812+3.618744=5.296556= 0.2(8.38906) + 0.4(9.04686) = 1.677812 + 3.618744 = 5.296556

Thus, the approximate value for the area of RR is: Aapprox5.2966text(to4significantfigures:5.297)A \\approx 5.2966 \\text{ (to 4 significant figures: } 5.297)

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