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This question is about an experiment to measure the Planck constant $h$ using light-emitting diodes (LEDs) - OCR - A-Level Physics A - Question 7 - 2013 - Paper 1

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This question is about an experiment to measure the Planck constant $h$ using light-emitting diodes (LEDs). (a) Each LED used in the experiment emits monochromatic ... show full transcript

Worked Solution & Example Answer:This question is about an experiment to measure the Planck constant $h$ using light-emitting diodes (LEDs) - OCR - A-Level Physics A - Question 7 - 2013 - Paper 1

Step 1

Explain the meaning of this equation in words.

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Answer

The equation eVmin=h/λe V_{min} = h / \lambda relates the energy of a photon emitted by the LED to its wavelength. Here, ee is the charge of an electron, VminV_{min} is the minimum voltage needed for the LED to emit light, hh is the Planck constant, and λ\lambda is the wavelength of the emitted photon. This means that higher energy (shorter wavelength) photons require a higher minimum voltage to be emitted, illustrating the quantum nature of light.

Step 2

Describe the experiment that uses the circuit of Fig. 7.1.

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Answer

In this experiment, the circuit with LEDs of different colors is connected to a power source. Each LED has a corresponding wavelength and is tested by gradually increasing the voltage until the LED lights up. The minimum voltage (VminV_{min}) at which each LED emits light is recorded. This data is then used to plot a graph of VminV_{min} against 1/λ1/\lambda, allowing for the analysis of the relationship between the energy of the emitted photons and their wavelengths.

Step 3

Complete the table and use the data to complete the graph of Fig. 7.2.

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To complete the table with average VminV_{min} values, input the values corresponding to the given wavelengths. Draw the line of best fit on the graph, using the plotted points. The slope or gradient of this line is to be calculated, which should approximate 1.2×10−6  Vm1.2 \times 10^{-6} \; V m.

Step 4

Use the equation given in (a) to show that the gradient of the line in Fig. 7.2 is equal to $h/c/e$.

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Answer

From the equation eVmin=h/λe V_{min} = h / \lambda, if we rearrange, the gradient of the graph (Vmin1/λ\frac{V_{min}}{1/\lambda}) is directly related to the constants hh, cc, and ee. This relationship can be established by recognizing that the gradient can be expressed as h/eh/e. Thus, incorporating the speed of light shows that the gradient is equal to h/c/eh/c/e.

Step 5

Calculate a value for the Planck constant using your value in (i).

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Answer

To calculate the Planck constant, we will use the gradient found from the line of best fit. If the gradient is determined to be approximately 1.2×10−6  Vm1.2 \times 10^{-6} \; V m, we can rearrange the equation mentioned earlier to find hh. Therefore, applying the previous relationship, we can derive that:

h=ext(gradient)×c×eh = ext{(gradient)} \times c \times e

Where cc is the speed of light and ee is the elementary charge. Once substituted with values for cc and ee, you get an estimate for hh.

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