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What equation links current (I), potential difference (V) and power (P)? Tick (✓) one box - AQA - GCSE Physics - Question 11 - 2022 - Paper 1

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What equation links current (I), potential difference (V) and power (P)? Tick (✓) one box. P = V × I When a person walks on a tile, a potential difference of 40 V ... show full transcript

Worked Solution & Example Answer:What equation links current (I), potential difference (V) and power (P)? Tick (✓) one box - AQA - GCSE Physics - Question 11 - 2022 - Paper 1

Step 1

What equation links current (I), potential difference (V) and power (P)?

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Answer

The correct equation that links current (I), potential difference (V), and power (P) is:

P=V×IP = V \times I

Step 2

Calculate the current in the tile.

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Answer

To calculate the current (I) in the tile, we use the formula:

P=V×IP = V \times I

Given:

  • Power output, P=4.4 WP = 4.4 \text{ W}
  • Potential difference, V=40 VV = 40 \text{ V}

Substituting the known values:

4.4=40×I4.4 = 40 \times I

Now, solve for I:

I=4.440=0.11 AI = \frac{4.4}{40} = 0.11 \text{ A}

Step 3

What equation links efficiency, total power input and useful power output?

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Answer

The equation that links efficiency, useful power output, and total power input is:

Efficiency=Useful power outputTotal power input\text{Efficiency} = \frac{\text{Useful power output}}{\text{Total power input}}

Step 4

Calculate the useful power output of the LED light.

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Answer

To find the useful power output of the LED light, we use the efficiency formula:

Efficiency=Useful power outputTotal power input\text{Efficiency} = \frac{\text{Useful power output}}{\text{Total power input}}

Given:

  • Efficiency = 0.85
  • Total power input = 4.0 W

We rearrange the formula to find the useful power output:

Useful power output=Efficiency×Total power input\text{Useful power output} = \text{Efficiency} \times \text{Total power input}

Substituting the known values:

Useful power output=0.85×4.0=3.4 W\text{Useful power output} = 0.85 \times 4.0 = 3.4 \text{ W}

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