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(a) (i) Ethanoic acid, CH₃COOH, reacts with ethanol to form ethyl ethanoate and water - Edexcel - GCSE Chemistry - Question 5 - 2016 - Paper 1

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(a) (i) Ethanoic acid, CH₃COOH, reacts with ethanol to form ethyl ethanoate and water. Complete the equation for the reaction by adding the formula of ethyl ethanoa... show full transcript

Worked Solution & Example Answer:(a) (i) Ethanoic acid, CH₃COOH, reacts with ethanol to form ethyl ethanoate and water - Edexcel - GCSE Chemistry - Question 5 - 2016 - Paper 1

Step 1

Complete the equation for the reaction by adding the formula of ethyl ethanoate.

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Answer

The balanced chemical equation for the reaction between ethanoic acid and ethanol to form ethyl ethanoate and water is:

CH3COOH+C2H5OHCH3COOC2H5+H2O\text{CH}_3\text{COOH} + \text{C}_2\text{H}_5\text{OH} \rightarrow \text{CH}_3\text{COOC}_2\text{H}_5 + \text{H}_2\text{O}

Step 2

State what you would see if solid calcium carbonate is added to some dilute ethanoic acid.

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Answer

When solid calcium carbonate is added to dilute ethanoic acid, you would observe effervescence or fizzing due to the evolution of carbon dioxide gas. Additionally, the solid may begin to dissolve as the reaction proceeds.

Step 3

Complete the sentence by putting a cross (X) in the box next to your answer.

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Answer

To find the concentration of ethanoic acid:

Given:

  • Mass of ethanoic acid = 6.0 g
  • Relative molecular mass = 60 g/mol

First, calculate the number of moles of ethanoic acid:

n=massmolar mass=6.060=0.1 moln = \frac{\text{mass}}{\text{molar mass}} = \frac{6.0}{60} = 0.1 \text{ mol}

Next, since the volume of the solution is 1.0 dm³:

Concentration=nVolume=0.11.0=0.1 mol dm3\text{Concentration} = \frac{n}{\text{Volume}} = \frac{0.1}{1.0} = 0.1 \text{ mol dm}^{-3}

Thus, the answer is A 0.1.

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