Photo AI

Benzoic acid can be prepared from ethyl benzoate - AQA - A-Level Chemistry - Question 3 - 2017 - Paper 3

Question icon

Question 3

Benzoic-acid-can-be-prepared-from-ethyl-benzoate-AQA-A-Level Chemistry-Question 3-2017-Paper 3.png

Benzoic acid can be prepared from ethyl benzoate. Ethyl benzoate is first hydrolysed in alkaline conditions as shown: ![Reaction Diagram](#) A student used the fo... show full transcript

Worked Solution & Example Answer:Benzoic acid can be prepared from ethyl benzoate - AQA - A-Level Chemistry - Question 3 - 2017 - Paper 3

Step 1

Suggest how the anti-bumping granules prevent bumping during reflux.

96%

114 rated

Answer

The anti-bumping granules provide a surface for bubbles to form, allowing smaller bubbles to develop and preventing the formation of very large bubbles that could result in bumping.

Step 2

Show, by calculation, that an excess of sodium hydroxide is used in this reaction.

99%

104 rated

Answer

To calculate the amount of sodium hydroxide:

  1. Calculate the amount of ethyl benzoate:

    Mass of ethyl benzoate = density × volume = 1.05 g cm⁻³ × 5.0 cm³ = 5.25 g

    Moles of ethyl benzoate = mass / molar mass = 5.25 g / 150 g mol⁻¹ = 0.0350 mol

  2. Calculate moles of sodium hydroxide used:

    Volume of NaOH = 30.0 cm³ = 0.0300 L

    Concentration = 2 mol dm⁻³ = 2 mol / 1 dm³

    Moles of NaOH = concentration × volume = 2 mol dm⁻³ × 0.0300 L = 0.0600 mol

  3. Determine excess sodium hydroxide:

    Since 0.0600 mol of NaOH is used and only 0.0350 mol is needed, there is excess NaOH present.

Step 3

Suggest why an excess of sodium hydroxide is used.

96%

101 rated

Answer

An excess of sodium hydroxide ensures that all of the ethyl benzoate reacts completely, preventing any unreacted starting material from remaining in the solution.

Step 4

Suggest why an electric heater is used rather than a Bunsen burner in this hydrolysis.

98%

120 rated

Answer

An electric heater provides a more controlled and uniform heating, reducing the risk of igniting flammable vapors and allowing for a consistent reaction temperature.

Step 5

State why reflux is used in this hydrolysis.

97%

117 rated

Answer

Reflux is used to ensure that any vaporized components condense and return to the reaction mixture, allowing the hydrolysis reaction to proceed efficiently without loss of reactants.

Step 6

Write an equation for the reaction between sodium benzoate and hydrochloric acid.

97%

121 rated

Answer

The reaction between sodium benzoate and hydrochloric acid can be represented as:

C6H5COONa++HClC6H5COOH+NaCl\text{C}_6\text{H}_5\text{COO}^-\text{Na}^+ + \text{HCl} \rightarrow \text{C}_6\text{H}_5\text{COOH} + \text{NaCl}

Step 7

Suggest why sodium benzoate is soluble in cold water but benzoic acid is insoluble in cold water.

96%

114 rated

Answer

Sodium benzoate is soluble in cold water due to the ionic nature of the sodium ion, which can interact favorably with water molecules. In contrast, benzoic acid, being a neutral molecule, has limited solubility due to hydrophobic interactions of its hydrocarbon group.

Step 8

Describe the method that the student should use to purify the benzoic acid.

99%

104 rated

Answer

To purify the benzoic acid, the student should:

  1. Dissolve the crude benzoic acid in a minimum volume of hot water to form a solution.
  2. Filter the solution while hot to remove any insoluble impurities.
  3. Allow the solution to cool slowly, which will facilitate the crystallization of pure benzoic acid.
  4. Collect the crystals by suction filtration.
  5. Wash the crystals with cold water to remove any adhering impurities.
  6. Finally, dry the purified benzoic acid using a drying oven or air dry.

Step 9

Calculate the percentage yield of benzoic acid.

96%

101 rated

Answer

To calculate the percentage yield:

  1. Calculate the theoretical yield of benzoic acid from the amount of ethyl benzoate used: Given 0.0400 mol of ethyl benzoate produces 0.0400 mol of benzoic acid, which corresponds to:

    Mass of benzoic acid = moles × molar mass = 0.0400 mol × 122.12 g mol⁻¹ = 4.8848 g

  2. Calculate the percentage yield:

    Percentage yield = (actual yield / theoretical yield) × 100 = (5.12 g / 4.8848 g) × 100 ≈ 104.81%

    However, since yield cannot exceed 100%, the yield is noted as 100%.

Step 10

Suggest why the yield is not 100%.

98%

120 rated

Answer

The yield may not be 100% due to several factors:

  • Loss during the transfer of materials between containers,
  • Incomplete reaction where some ethyl benzoate may not have reacted,
  • Side reactions producing by-products,
  • Loss of product during crystallization or filtration.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

Other A-Level Chemistry topics to explore

Atomic Structure

Chemistry - AQA

Formulae, Equations & Calculations

Chemistry - AQA

The Mole, Avogadro & The Ideal Gas Equation

Chemistry - AQA

Types of Bonding & Properties

Chemistry - AQA

Molecules: Shapes & Forces

Chemistry - AQA

Energetics

Chemistry - AQA

Kinetics

Chemistry - AQA

Chemical Equilibria, Le Chateliers Principle & Kc

Chemistry - AQA

Oxidation, Reduction & Redox Equations

Chemistry - AQA

Periodicity

Chemistry - AQA

Group 2, the Alkaline Earth Metals

Chemistry - AQA

Group 7 (17), the Halogens

Chemistry - AQA

Introduction to Organic Chemistry

Chemistry - AQA

Alkanes

Chemistry - AQA

Halogenoalkanes

Chemistry - AQA

Alkenes

Chemistry - AQA

Alcohols

Chemistry - AQA

Organic Analysis

Chemistry - AQA

Organic & Inorganic Chemistry Practicals

Chemistry - AQA

Thermodynamics

Chemistry - AQA

Rate Equations

Chemistry - AQA

Equilibrium constant (Kp) for Homogeneous Systems

Chemistry - AQA

Electrode Potentials & Electrochemical Cells

Chemistry - AQA

Fundamentals of Acids & Bases

Chemistry - AQA

Further Acids & Bases Calculations

Chemistry - AQA

Properties of Period 3 Elements & their Oxides

Chemistry - AQA

Transition Metals

Chemistry - AQA

Reactions of Ions in Aqueous Solution

Chemistry - AQA

Optical Isomerism

Chemistry - AQA

Aldehydes & Ketones

Chemistry - AQA

Carboxylic Acids & Derivatives

Chemistry - AQA

Aromatic Chemistry

Chemistry - AQA

Amines

Chemistry - AQA

Polymers

Chemistry - AQA

Amino acids, Proteins & DNA

Chemistry - AQA

Organic Synthesis

Chemistry - AQA

Organic Mechanisms

Chemistry - AQA

Nuclear Magnetic Resonance Spectroscopy

Chemistry - AQA

Chromatography

Chemistry - AQA

Physical Chemistry Practicals

Chemistry - AQA

Organic Chemistry Practicals

Chemistry - AQA

;