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Question 3
Benzoic acid can be prepared from ethyl benzoate. Ethyl benzoate is first hydrolysed in alkaline conditions as shown:  A student used the fo... show full transcript
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Answer
To calculate the amount of sodium hydroxide:
Calculate the amount of ethyl benzoate:
Mass of ethyl benzoate = density × volume = 1.05 g cm⁻³ × 5.0 cm³ = 5.25 g
Moles of ethyl benzoate = mass / molar mass = 5.25 g / 150 g mol⁻¹ = 0.0350 mol
Calculate moles of sodium hydroxide used:
Volume of NaOH = 30.0 cm³ = 0.0300 L
Concentration = 2 mol dm⁻³ = 2 mol / 1 dm³
Moles of NaOH = concentration × volume = 2 mol dm⁻³ × 0.0300 L = 0.0600 mol
Determine excess sodium hydroxide:
Since 0.0600 mol of NaOH is used and only 0.0350 mol is needed, there is excess NaOH present.
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Answer
Sodium benzoate is soluble in cold water due to the ionic nature of the sodium ion, which can interact favorably with water molecules. In contrast, benzoic acid, being a neutral molecule, has limited solubility due to hydrophobic interactions of its hydrocarbon group.
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To purify the benzoic acid, the student should:
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Answer
To calculate the percentage yield:
Calculate the theoretical yield of benzoic acid from the amount of ethyl benzoate used: Given 0.0400 mol of ethyl benzoate produces 0.0400 mol of benzoic acid, which corresponds to:
Mass of benzoic acid = moles × molar mass = 0.0400 mol × 122.12 g mol⁻¹ = 4.8848 g
Calculate the percentage yield:
Percentage yield = (actual yield / theoretical yield) × 100 = (5.12 g / 4.8848 g) × 100 ≈ 104.81%
However, since yield cannot exceed 100%, the yield is noted as 100%.
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Answer
The yield may not be 100% due to several factors:
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