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Iodide ions are oxidised to iodine by hydrogen peroxide in acidic conditions - AQA - A-Level Chemistry - Question 1 - 2018 - Paper 3

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Iodide ions are oxidised to iodine by hydrogen peroxide in acidic conditions. H2O2(aq) + 2H+(aq) + 2I-(aq) → I2(aq) + 2H2O(l) The rate equation for this reaction c... show full transcript

Worked Solution & Example Answer:Iodide ions are oxidised to iodine by hydrogen peroxide in acidic conditions - AQA - A-Level Chemistry - Question 1 - 2018 - Paper 3

Step 1

Explain why the use of a large excess of H2O2 and I- means that the rate of reaction at a fixed temperature depends only on the concentration of H+(aq).

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Answer

The use of a large excess of H2O2 and I- ensures that their concentrations remain effectively constant throughout the reaction. Because these reactants do not change significantly during the course of the reaction, the rate is influenced solely by the concentration of H+(aq). Therefore, the rate of reaction can be stated as directly proportional to the concentration of H+(aq) under these conditions.

Step 2

State and explain what must be done to each sample before it is titrated with alkali.

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Answer

Each sample must be quenched immediately after being taken to stop the reaction. This can be achieved by diluting the sample with a known volume of distilled water or by adding a reagent that reacts with H2O2. This ensures that the concentration of H+(aq) remains unchanged during the titration process and allows accurate measurement of its concentration.

Step 3

Explain how the graph shows that the order with respect to H+(aq) is zero.

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Answer

The graph shows a linear relationship between the concentration of H+(aq) and time, indicating that the concentration decreases at a constant rate. If the order with respect to H+(aq) were greater than zero, the graph would show a curved line as the rate of reaction would change as the concentration decreases. The straight line indicates zero order, where the reaction rate is independent of the concentration of H+(aq).

Step 4

Use the graph in Figure 1 to calculate the value of k1. Give the units of k1.

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Answer

To determine k1, we take the slope of the graph, which represents the rate of change of concentration with respect to time. By selecting points on the straight line and using the formula

k1=Δ[H+]Δtk_1 = -\frac{\Delta[H^+]}{\Delta t}

we can substitute values taken from the graph. The units for k1 are mol dm^-3 s^-1.

Step 5

Plot these results on the grid in Figure 2.

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Answer

The data from Table 1 should be plotted on the provided grid, ensuring all points are accurately represented with their respective time and concentration values.

Step 6

Draw a line of best fit on the grid in Figure 2.

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Answer

A smooth curve should be drawn that best represents the trend of the plotted points, encompassing the first three plotted points to provide an accurate representation of the data.

Step 7

Calculate the rate of reaction when [H+] = 0.35 mol dm-3. Show your working using a suitable construction on the graph in Figure 2.

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Answer

Using a tangent at the point where [H+] = 0.35 mol dm-3, the slope of this line will indicate the rate of reaction. By following the constructed tangent to derive the corresponding rate of change from the graph, we can use this to state the rate of reaction accordingly.

Step 8

Explain how you could use a series of experiments to determine the order of this reaction with respect to A.

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Answer

To determine the order of the reaction with respect to A, a series of experiments can be set up where the initial concentration of A is varied while keeping the concentrations of B, C, and X constant. The initial rate of reaction can be measured by assessing the color change due to E being produced. By plotting these initial rates against the varying concentrations of A, the order of reaction with respect to A can be determined using the method of initial rates.

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