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A planet of radius $R$ and mass $M$ has a gravitational field strength of $g$ at its surface - AQA - A-Level Physics - Question 9 - 2022 - Paper 2

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A planet of radius $R$ and mass $M$ has a gravitational field strength of $g$ at its surface. Which row describes a planet with a gravitational field strength of $4... show full transcript

Worked Solution & Example Answer:A planet of radius $R$ and mass $M$ has a gravitational field strength of $g$ at its surface - AQA - A-Level Physics - Question 9 - 2022 - Paper 2

Step 1

Determine the gravitational field strength formula

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Answer

The gravitational field strength at the surface of a planet is given by the formula: g=GMR2g = \frac{GM}{R^2} where GG is the universal gravitational constant. For a planet with gravitational field strength 4g4g, we have: 4g=GM′R′24g = \frac{GM'}{R'^2} where M′M' is the mass of the new planet and R′R' is its radius.

Step 2

Set up the relationship between the two planets

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Answer

Equating the two expressions for gravitational field strength: 4(GMR2)=GM′R′24 \left( \frac{GM}{R^2} \right) = \frac{GM'}{R'^2} Dividing both sides by GG and rearranging gives: 4M=M′R2R′24M = \frac{M'R^2}{R'^2} This can be rewritten to find a relationship between the mass and radius of the new planet: M′=4MR′2R2M' = 4M \frac{R'^2}{R^2}

Step 3

Evaluate the options

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Answer

We can evaluate the given options:

  1. Row A: Radius 2R2R, Mass 2M2M:

    • M′=4M(2R)2R2=4Mâ‹…4=16MM' = 4M \frac{(2R)^2}{R^2} = 4M \cdot 4 = 16M, (incorrect)
  2. Row B: Radius R2\frac{R}{\sqrt{2}}, Mass M2\frac{M}{2}:

    • M′=4M(R2)2R2=4Mâ‹…12=2MM' = 4M \frac{(\frac{R}{\sqrt{2}})^2}{R^2} = 4M \cdot \frac{1}{2} = 2M, (incorrect)
  3. Row C: Radius RR, Mass M2\frac{M}{\sqrt{2}}:

    • M′=4MR2R2=4MM' = 4M \frac{R^2}{R^2} = 4M, (incorrect)
  4. Row D: Radius R2\frac{R}{\sqrt{2}}, Mass 2M2M:

    • M′=4M(R2)2R2=4Mâ‹…12=2MM' = 4M \frac{(\frac{R}{\sqrt{2}})^2}{R^2} = 4M \cdot \frac{1}{2} = 2M, (correct)

From the evaluation, Row D provides a condition in which the gravitational field strength is 4g4g.

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