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2 (a) Complete the electron configurations for Ni and Ni²⁺ - CIE - A-Level Chemistry - Question 2 - 2014 - Paper 1

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2 (a) Complete the electron configurations for Ni and Ni²⁺. Ni Ni²⁺ (b) The presence of electrons in d orbitals is responsible for the colours of transition eleme... show full transcript

Worked Solution & Example Answer:2 (a) Complete the electron configurations for Ni and Ni²⁺ - CIE - A-Level Chemistry - Question 2 - 2014 - Paper 1

Step 1

Complete the electron configurations for Ni and Ni²⁺.

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Answer

The electron configuration for nickel (Ni) can be written as:

Ni: [Ar] 3d⁸ 4s²

For the nickel ion Ni²⁺, which has lost two electrons, the configuration becomes:

Ni²⁺: [Ar] 3d⁸

Step 2

What term is used to describe orbitals that are at the same energy level?

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Answer

The term used to describe orbitals that are at the same energy level is 'degenerate'.

Step 3

Complete the diagram to show the splitting of the d orbital energy levels in an octahedral complex ion.

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Answer

In an octahedral complex, the five d orbitals split into two sets: the lower energy set comprising three orbitals (t₂g) and the higher energy set comprising two orbitals (e_g). Thus, the correct diagram should show three orbitals at the lower energy level and two at the higher energy level.

Step 4

On the axes below, sketch the shapes of one d orbital from the lower energy level and one d orbital from the higher energy level.

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Answer

The lower energy d orbitals (t₂g) can be represented by the shapes of d_xy, d_xz, and d_yz, which are cloverleaf-shaped. The higher energy d orbitals (e_g) can be represented by d_x²-y² and d_z², which have different shapes. The sketches should indicate these distinct geometries.

Step 5

Explain the origin of the colour of the complex [Ni(H₂O)₆]²⁺.

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Answer

The green colour of the complex [Ni(H₂O)₆]²⁺ arises from the d-d electronic transitions. Electrons in the lower energy d orbitals can absorb light energy (blue or red) to transition to higher energy d orbitals, resulting in the complementary colour being observed, which is green.

Step 6

Suggest formulae for A and B and write equations for the two reactions producing A and B.

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Answer

The formula for the grey-green precipitate A formed when NH₃ is added is [Ni(OH)₂]. The formula for the blue-violet solution B after further addition of NH₃ is [Ni(NH₃)₆]²⁺. The reactions can be summarized as:

[ ext{[Ni(H₂O)₆]}^{2+} + 2 ext{NH₃} \rightarrow ext{[Ni(NH₃)₂(H₂O)₄]}^{2+} + 2 ext{H₂O} \ ext{(Formation of A)}]

[ ext{[Ni(H₂O)₆]}^{2+} + 6 ext{NH₃} \rightarrow ext{[Ni(NH₃)₆]}^{2+} + 6 ext{H₂O} \ ext{(Formation of B)}]

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