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The hydrolysis of 1-chloropropane to produce propan-1-ol is much slower than the corresponding hydrolysis of 1-iodopropane - CIE - A-Level Chemistry - Question 23 - 2014 - Paper 1
Question 23
The hydrolysis of 1-chloropropane to produce propan-1-ol is much slower than the corresponding hydrolysis of 1-iodopropane. Which statement explains this observatio... show full transcript
Worked Solution & Example Answer:The hydrolysis of 1-chloropropane to produce propan-1-ol is much slower than the corresponding hydrolysis of 1-iodopropane - CIE - A-Level Chemistry - Question 23 - 2014 - Paper 1
Step 1
The bond strength of the C–I bond is less than that of the C–Cl bond.
Answer
The hydrolysis reaction involves the breaking of the carbon-halogen bond. Since the C–I bond is weaker than the C–Cl bond, it will break more easily, leading to a faster hydrolysis rate for 1-iodopropane compared to 1-chloropropane. This discrepancy in bond strength explains why the hydrolysis of 1-chloropropane is much slower.