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In the hydrolysis of bromoethane by aqueous sodium hydroxide, what is the nature of the attacking group and of the leaving group? | attacking group | leaving group | |-----------------|---------------| | A | electrophile | | B | electrophile | | C | nucleophile | | D | nucleophile | - CIE - A-Level Chemistry - Question 25 - 2014 - Paper 1
Question 25
In the hydrolysis of bromoethane by aqueous sodium hydroxide, what is the nature of the attacking group and of the leaving group? | attacking group | leaving group ... show full transcript
Worked Solution & Example Answer:In the hydrolysis of bromoethane by aqueous sodium hydroxide, what is the nature of the attacking group and of the leaving group? | attacking group | leaving group | |-----------------|---------------| | A | electrophile | | B | electrophile | | C | nucleophile | | D | nucleophile | - CIE - A-Level Chemistry - Question 25 - 2014 - Paper 1
Step 1
Step 2
leaving group
Answer
The leaving group in this reaction is bromide (Br-). Bromine is a good leaving group due to its ability to stabilize the negative charge after departing from the substrate. Thus, during hydrolysis, the bond between the carbon and bromine breaks, allowing the nucleophile, hydroxide, to bond with the carbon.