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4 (a) (i) Define the term standard cell potential, $E^{ ext{o}}_{cell}$ - CIE - A-Level Chemistry - Question 4 - 2016 - Paper 1

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4 (a) (i) Define the term standard cell potential, $E^{ ext{o}}_{cell}$. Standard cell potential, $E^{ ext{o}}_{cell}$, is the electromotive force (EMF) or potentia... show full transcript

Worked Solution & Example Answer:4 (a) (i) Define the term standard cell potential, $E^{ ext{o}}_{cell}$ - CIE - A-Level Chemistry - Question 4 - 2016 - Paper 1

Step 1

Define the term standard cell potential, $E^{ ext{o}}_{cell}$

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Answer

Standard cell potential, EcellextoE^{ ext{o}}_{cell}, refers to the electromotive force (EMF) or potential difference between two electrodes (or half cells) under standard conditions (temperature of 298 K and concentration of 1 mol dm3^{-3}).

Step 2

Complete the diagram, labelling the components you add

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Answer

The components to be added are a voltmeter and a salt bridge.

Step 3

Identify the components A-D

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Answer

A. Ag+^{+}(aq) B. Ag (s) C. Pt (s) D. Fe2+^{2+}(aq) and Fe (s)

Step 4

Use $E^{ ext{o}}$ values to write an equation for the cell reaction that takes place if the two electrodes in (a) are connected by a wire and the circuit is completed

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Answer

The cell reaction can be represented as:
Ag+^{+}(aq) + Fe (s) → Ag (s) + Fe2+^{2+}(aq)

Step 5

Another electrochemical cell was set up using 0.31 mol dm$^{-3}$ Ag$^{+}$(aq) instead of the standard Ag solution

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Answer

Using the Nernst equation:
E=Eexto+0.059extlog[Ag+](aq)E = E^{ ext{o}} + 0.059 ext{log}[Ag^+](aq)
Substituting the given values:
E=0.800.03=0.77E = 0.80 - 0.03 = 0.77 V
Thus, the new Ecell=0.77E_{cell} = 0.77 V.

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