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A student is investigating stationary waves in the air column inside a tube, using the apparatus shown in Fig - OCR - A-Level Physics A - Question 5 - 2021 - Paper 1

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A student is investigating stationary waves in the air column inside a tube, using the apparatus shown in Fig. 5.1. The loudspeaker emits sound of frequency $f$ and... show full transcript

Worked Solution & Example Answer:A student is investigating stationary waves in the air column inside a tube, using the apparatus shown in Fig - OCR - A-Level Physics A - Question 5 - 2021 - Paper 1

Step 1

Explain how a stationary wave of fundamental frequency is produced and state the relationship between l and λ.

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Answer

A stationary wave of fundamental frequency is produced when the sound waves emitted by the loudspeaker reflect off the boundaries of the tube, superposing with incoming waves to create nodes and antinodes. The fundamental frequency corresponds to the simplest mode of vibration. The relationship between the length of the air column, ll, and the wavelength, λ\lambda, is given by:

l=λ4 l = \frac{\lambda}{4}

, since the fundamental frequency has one node at the closed end (the water surface) and one antinode at the open end.

Step 2

Show that the line of best fit has gradient = v/4 and y-intercept = -k.

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Answer

To show this, we start with the equation:

4(l+k)=vf4(l + k) = \frac{v}{f}

This can be rearranged to find ff:

f=v4(l+k) f = \frac{v}{4(l + k)}

When plotted as rac{1}{f} against rac{1}{\lambda}, the gradient of the line corresponds to v4\frac{v}{4} and the intercept will be k-k.

Step 3

Calculate v from the gradient of the line of best fit.

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Answer

Using the gradient mm from the line of best fit, we can express it as

m=v4 m = \frac{v}{4}

Thus, to find the speed of sound vv, we rearrange the formula to get:

v=4m v = 4m

Calculating this with the obtained gradient will yield the value for vv in m/s.

Step 4

Use the line of best fit on the graph to estimate F.

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Answer

To estimate the frequency FF using the line of best fit, plug in the corresponding value of rac{1}{\lambda} from the graph into the derived equation for frequency, f=1m(1λ)f = \frac{1}{m \cdot (\frac{1}{\lambda})}, providing you with the estimated frequency value.

Step 5

Write an expression for the percentage uncertainty in the value of F.

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Answer

The percentage uncertainty in the value of FF is given by:

Percentage Uncertainty=100ΔFF\text{Percentage Uncertainty} = 100 \frac{\Delta F}{F}

Using the rules for uncertainties, this can be expressed as:

ΔFF=Δvv+Δll+Δkk \frac{\Delta F}{F} = \frac{\Delta v}{v} + \frac{\Delta l}{l} + \frac{\Delta k}{k}

Thus, substituting this into the previous equation provides the full expression needed.

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