Figure 6 shows an unusually shaped container. The container has four vertical tubes of different shape and size. Figure 6 Water is poured into the container up to the level shown in tube 1. 04.1 Complete Figure 6 to show the height of the water in tubes 2, 3 and 4. [1 mark] 04.2 The further a swimmer dives below the surface of the sea, the greater the pressure on the swimmer. Explain why. [2 marks] 04.3 A person swims from a depth of 0.50 m to a depth of 1.70 m below the surface of the sea. density of the sea water = 1030 kg/m³ gravitational field strength = 9.8 N/kg Calculate the increase in pressure on the swimmer. Give the unit. Use an equation from the Physics Equation Sheet. [4 marks]

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Figure 6 shows an unusually shaped container - AQA - GCSE Physics - Question 4 - 2018 - Paper 1

Question 4

Figure 6 shows an unusually shaped container. The container has four vertical tubes of different shape and size. Figure 6 Water is poured into the container up to... show full transcript

Worked Solution & Example Answer:Figure 6 shows an unusually shaped container - AQA - GCSE Physics - Question 4 - 2018 - Paper 1

Step 1

Complete Figure 6 to show the height of the water in tubes 2, 3 and 4.

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Answer

The heights in tubes 2, 3, and 4 should be drawn to match the height of the water in tube 1. This reflects the principle of communicating vessels, where the height of the liquid remains constant across connected tubes.

Step 2

Explain why.

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Answer

Increasing depth increases the height of the water column above the swimmer, which increases the weight and the pressure exerted on the swimmer. This means that as the swimmer dives deeper, the pressure from the water above him increases.

Step 3

Calculate the increase in pressure on the swimmer.

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Answer

The increase in depth is calculated as follows:

$ext{Increase in depth} = 1.70 ext{ m} - 0.50 ext{ m} = 1.20 ext{ m}$

Using the formula for pressure due to a fluid column:

ho g h $$ Where: - $ ho$ (density of sea water) = 1030 kg/m³ - $g$ (gravitational field strength) = 9.8 N/kg - $h$ (increase in depth) = 1.20 m Therefore, $$ P = 1030 imes 9.8 imes 1.20 = 12121.68 ext{ Pa} $$ The increase in pressure on the swimmer is approximately **12122 Pa**.

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Figure 6 shows an unusually shaped container - AQA - GCSE Physics - Question 4 - 2018 - Paper 1

Worked Solution & Example Answer:Figure 6 shows an unusually shaped container - AQA - GCSE Physics - Question 4 - 2018 - Paper 1

Complete Figure 6 to show the height of the water in tubes 2, 3 and 4.

Explain why.

Calculate the increase in pressure on the swimmer.

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