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Figure 12 shows a graph of current against potential difference for an electrical component - Edexcel - GCSE Physics - Question 6 - 2018 - Paper 1

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Figure 12 shows a graph of current against potential difference for an electrical component. Which electrical component will show this variation of current with pot... show full transcript

Worked Solution & Example Answer:Figure 12 shows a graph of current against potential difference for an electrical component - Edexcel - GCSE Physics - Question 6 - 2018 - Paper 1

Step 1

Which electrical component will show this variation of current with potential difference?

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Answer

The electrical component that will show this variation of current with potential difference is a D diode. This is because the current through a diode does not increase linearly with the potential difference, as seen in the provided graph where the current abruptly changes after a threshold potential difference.

Step 2

Calculate the power of the lamp.

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Answer

To calculate the power of the lamp, we will use the formula:

P=IimesVP = I imes V

Substituting the given values:

P=0.12imes0.24P = 0.12 imes 0.24

Now, we evaluate the multiplication:

P=0.0288extWP = 0.0288 ext{ W}

Therefore, the power of the lamp is 0.029 W when rounded to three decimal places.

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