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The voltage (potential difference) across a length of wire is 1.5V - Edexcel - GCSE Physics - Question 8 - 2023 - Paper 2

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The voltage (potential difference) across a length of wire is 1.5V. A charge of 0.042 C flows through the wire. Calculate the energy transferred. Use the equation... show full transcript

Worked Solution & Example Answer:The voltage (potential difference) across a length of wire is 1.5V - Edexcel - GCSE Physics - Question 8 - 2023 - Paper 2

Step 1

Calculate the energy transferred.

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Answer

To calculate the energy transferred, use the formula:

E=QimesVE = Q imes V

Substituting the values:

E=0.042extCimes1.5extVE = 0.042 ext{ C} imes 1.5 ext{ V}

This results in:

E=0.063extJE = 0.063 ext{ J}

Step 2

Add connecting wires, a voltmeter and an ammeter.

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Answer

The voltmeter should be connected in parallel with the iron wire, and the ammeter should be connected in series with the iron wire.

Step 3

Draw a straight line of best fit on Figure 21.

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Answer

Using the graph provided in Figure 21, draw a straight line that best represents the data points, ensuring that it has equal points of intersection above and below the line.

Step 4

Use Figure 21 to estimate the resistance of a 100 cm length of the iron wire.

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Answer

Reference the straight line of best fit to find the resistance corresponding to 100 cm from the graph.

Step 5

Calculate the resistance of this piece of wire.

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Answer

Using the formula V=IimesRV = I imes R rearranged to find resistance: R=VIR = \frac{V}{I} Substituting the known values: R=1.56extV0.45extA=3.47extΩR = \frac{1.56 ext{ V}}{0.45 ext{ A}} = 3.47 ext{ Ω}

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