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How much 0.2mol/dm³ hydrochloric acid solution could make from 100cm³ of 1.0mol/dm³ hydrochloric acid? A 20 cm³? B 200cm³? C 500cm³? D 600cm³? Your answer - OCR Gateway - GCSE Chemistry - Question 11 - 2018 - Paper 1

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Question 11

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How much 0.2mol/dm³ hydrochloric acid solution could make from 100cm³ of 1.0mol/dm³ hydrochloric acid? A 20 cm³? B 200cm³? C 500cm³? D 600cm³? Your answer

Worked Solution & Example Answer:How much 0.2mol/dm³ hydrochloric acid solution could make from 100cm³ of 1.0mol/dm³ hydrochloric acid? A 20 cm³? B 200cm³? C 500cm³? D 600cm³? Your answer - OCR Gateway - GCSE Chemistry - Question 11 - 2018 - Paper 1

Step 1

Calculate the number of moles in the 100 cm³ of 1.0 mol/dm³ hydrochloric acid

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Answer

To find the number of moles (n) in the hydrochloric acid solution, use the formula:

n=CimesVn = C imes V

Where:

  • CC is the concentration in mol/dm³
  • VV is the volume in dm³

First, convert the volume from cm³ to dm³:

100extcm3=0.1extdm3100 ext{ cm}^3 = 0.1 ext{ dm}^3

Now, calculate:

n=1.0extmol/dm3imes0.1extdm3=0.1extmolesn = 1.0 ext{ mol/dm}^3 imes 0.1 ext{ dm}^3 = 0.1 ext{ moles}

Step 2

Determine the volume of 0.2 mol/dm³ solution that can be made

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Answer

Next, we need to find out how much volume (V) of 0.2 mol/dm³ solution can be produced with 0.1 moles of hydrochloric acid. Rearranging the formula:

V=nCV = \frac{n}{C}

Substituting the values:

V=0.1extmoles0.2extmol/dm3=0.5extdm3V = \frac{0.1 ext{ moles}}{0.2 ext{ mol/dm}^3} = 0.5 ext{ dm}^3

Convert the volume from dm³ to cm³:

0.5extdm3=500extcm30.5 ext{ dm}^3 = 500 ext{ cm}^3

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