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Nina estimates the value of \( rac{\sqrt{3.93 \times 393^3}}{0.546 \times 220}\) by rounding each number to 1 significant figure - OCR - GCSE Maths - Question 4 - 2020 - Paper 6

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Question 4

Nina-estimates-the-value-of--\(-rac{\sqrt{3.93-\times-393^3}}{0.546-\times-220}\)-by-rounding-each-number-to-1-significant-figure-OCR-GCSE Maths-Question 4-2020-Paper 6.png

Nina estimates the value of \( rac{\sqrt{3.93 \times 393^3}}{0.546 \times 220}\) by rounding each number to 1 significant figure. (a) Show that Nina’s answer is 64... show full transcript

Worked Solution & Example Answer:Nina estimates the value of \( rac{\sqrt{3.93 \times 393^3}}{0.546 \times 220}\) by rounding each number to 1 significant figure - OCR - GCSE Maths - Question 4 - 2020 - Paper 6

Step 1

(a) Show that Nina’s answer is 64.

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Answer

To estimate the expression, we need to round each number to 1 significant figure:

  • Round 3.93 to 4
  • Round 393 to 400
  • Round 0.546 to 0.5
  • Round 220 to 200

Now substituting these rounded values:

[ \frac{\sqrt{4 \times (400)^3}}{0.5 \times 200} = \frac{\sqrt{4 \times 64000000}}{100} = \frac{\sqrt{256000000}}{100} = \frac{16000}{100} = 160 ]

The estimated value for Nina’s calculation is:

[ \frac{160}{100} = 64 ]

Thus, Nina’s answer is confirmed to be 64.

Step 2

(b) Calculate the error in her estimated answer as a percentage of the exact answer.

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Answer

To compute the error, we need to determine the exact value of the expression without rounding:

  1. Calculate the exact value:

    • Exact value = ( \frac{\sqrt{3.93 \times 393^3}}{0.546 \times 220} )
  2. Compute the estimated value:

    • Estimated Value = 64
  3. Error Calculation:

    • Error = Exact Value - Estimated Value
    • Percentage Error = ( \frac{\text{Error}}{\text{Exact Value}} \times 100 %
  4. Substitute the values to find the percentage error.

The final result will give the percentage error of the estimation compared to the exact value.

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