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Under suitable conditions, 2-bromobutane reacts with sodium hydroxide to produce a mixture of five products, A, B, C, D and E - AQA - A-Level Chemistry - Question 3 - 2022 - Paper 3

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Under suitable conditions, 2-bromobutane reacts with sodium hydroxide to produce a mixture of five products, A, B, C, D and E. Products A, B and C are alkenes. A i... show full transcript

Worked Solution & Example Answer:Under suitable conditions, 2-bromobutane reacts with sodium hydroxide to produce a mixture of five products, A, B, C, D and E - AQA - A-Level Chemistry - Question 3 - 2022 - Paper 3

Step 1

Give the names of the two concurrent mechanisms responsible for the formation of the alkenes and the alcohols.

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Answer

Mechanism to form alkenes: Elimination (E2 mechanism for alkenes)

Mechanism to form alcohols: Nucleophilic substitution (S type mechanism for alcohols).

Step 2

Define the term stereoisomers.

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Answer

Stereoisomers are different compounds that have the same molecular formula and the same structural formula but differ in the spatial arrangement of atoms.

Step 3

Deduce the name of isomer A. Explain why A does not exhibit stereoisomerism.

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Answer

Name: But-2-ene (or 2-butene depending on context)

Explanation: A does not exhibit stereoisomerism because it does not have a C=C double bond capable of existing in cis/trans forms due to the lack of different substituents on the double-bonded carbons.

Step 4

Outline the mechanism for the reaction of 2-bromobutane with sodium hydroxide to form alkene A.

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Answer

  1. The hydroxide ion acts as a base and removes a proton from a hydrogen atom adjacent to the bromine-bearing carbon (deprotonation).

  2. This results in the formation of a double bond between the carbon atoms, while the bromide ion is expelled as a leaving group.

Step 5

Deduce the name of isomer B and the name of isomer C. Explain the origin of stereoisomerism in B and C.

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Answer

Names: B is cis-2-butene, C is trans-2-butene.

Explanation: The origin of stereoisomerism in B and C arises from the restricted rotation around the C=C double bond, which leads to different spatial arrangements of the substituents around the double bond.

Step 6

Draw 3D representations of enantiomers D and E to show how their structures are related.

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Answer

Enantiomers D and E can be represented in 3D as follows:

  • D: (S)-2-butanol

  • E: (R)-2-butanol

(Visual representation would typically include rotated structures showing stereochemistry.)

Step 7

State and explain the order in which precipitates appear.

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Answer

Order: 1-iodobutane > 1-bromobutane > 1-chlorobutane.

Explanation: The order of hydrolysis rates is based on the reactivity of the halogen; iodine is the best leaving group, followed by bromine and then chlorine. Therefore, 1-iodobutane hydrolyzes fastest, leading to the quickest formation of the precipitate.

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