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A sample of titanium was ionised by electron impact in a time of flight (TOF) mass spectrometer - AQA - A-Level Chemistry - Question 4 - 2017 - Paper 1

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A sample of titanium was ionised by electron impact in a time of flight (TOF) mass spectrometer. Information from the mass spectrum about the isotopes of titanium in... show full transcript

Worked Solution & Example Answer:A sample of titanium was ionised by electron impact in a time of flight (TOF) mass spectrometer - AQA - A-Level Chemistry - Question 4 - 2017 - Paper 1

Step 1

Calculate the relative atomic mass of titanium in this sample.

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Answer

To calculate the relative atomic mass (RAM) of titanium, we use the formula:

RAM=(m/z1×abundance1)+(m/z2×abundance2)+(m/z3×abundance3)+(m/z4×abundance4)Total abundance\text{RAM} = \frac{(m/z_1 \times \text{abundance}_1) + (m/z_2 \times \text{abundance}_2) + (m/z_3 \times \text{abundance}_3) + (m/z_4 \times \text{abundance}_4)}{\text{Total abundance}}

Applying the values from the table:

RAM=(46×1.9)+(47×7.8)+(48×74.6)+(49×8.5)1.9+7.8+74.6+8.5\text{RAM} = \frac{(46 \times 1.9) + (47 \times 7.8) + (48 \times 74.6) + (49 \times 8.5)}{1.9 + 7.8 + 74.6 + 8.5}

Calculating:

RAM=(87.4)+(374.6)+(3580.8)+(416.5)92.847.8\text{RAM} = \frac{(87.4) + (374.6) + (3580.8) + (416.5)}{92.8} \approx 47.8

Thus, the relative atomic mass of titanium is 47.8.

Step 2

Write an equation, including state symbols, to show how an atom of titanium is ionised by electron impact and give the m/z value of the ion that would reach the detector first.

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Answer

The ionisation of titanium by electron impact can be represented as:

Ti(g)+eTi+(g)+2e\text{Ti}(g) + e^- \rightarrow \text{Ti}^+(g) + 2e^-

The m/z value of the titanium ion that reaches the detector first is the mass over charge, where for the ion Ti+, m/z = 48.

Therefore, the m/z value is 48.

Step 3

Calculate the mass, in kg, of one atom of 4Ti.

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Answer

To calculate the mass of one atom of 4Ti, we can use the formula:

mass=molar massNA\text{mass} = \frac{\text{molar mass}}{N_A}

Where:

  • Molar mass of 4Ti is approximately 4 g/mol.
  • Avogadro's constant, NA=6.022×1023 mol1N_A = 6.022 \times 10^{23} \text{ mol}^{-1}.

Thus, the calculation becomes:

mass=4 g/mol6.022×1023 mol1=6.64×1024 kg\text{mass} = \frac{4 \text{ g/mol}}{6.022 \times 10^{23} \text{ mol}^{-1}} = 6.64 \times 10^{-24} \text{ kg}

So, the mass of one atom of 4Ti is approximately 6.64 x 10^-24 kg.

Step 4

Calculate the time of flight of the 'Ti' ion.

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Answer

Using the equation:

t=d2Emt = \frac{d}{\sqrt{\frac{2E}{m}}}

Where:

  • For the 'Ti' ion, the mass mm needs to be calculated based on the equation:
  • The kinetic energy E=1.013×103JE = 1.013 \times 10^{-3} J.

First, calculate mm: if for Ti, m=47.8extg/molm = 47.8 ext{ g/mol} then:

m=47.81000 kgm = \frac{47.8}{1000} \text{ kg}

Now, substitute mm back into the equation to find tt. Assuming dd is given or can be derived:

t=d2×1.013×103mt = \frac{d}{\sqrt{\frac{2 \times 1.013 \times 10^{-3}}{m}}}

With sufficient detail, this allows for a calculation of time of flight using parameters associated with the specific experimental setup.

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