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Benzene reacts with methanoyl chloride (HCOCl) in the presence of a catalyst - AQA - A-Level Chemistry - Question 8 - 2022 - Paper 2

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Benzene reacts with methanoyl chloride (HCOCl) in the presence of a catalyst. 08.1 Give an equation for the overall reaction when benzene reacts with methanoyl chlo... show full transcript

Worked Solution & Example Answer:Benzene reacts with methanoyl chloride (HCOCl) in the presence of a catalyst - AQA - A-Level Chemistry - Question 8 - 2022 - Paper 2

Step 1

08.1 Give an equation for the overall reaction when benzene reacts with methanoyl chloride. Name the organic product.

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Answer

The overall reaction can be represented as:

C6H6+HCOClC6H5CHO+HClC_6H_6 + HCOCl \rightarrow C_6H_5CHO + HCl

The organic product formed in this reaction is benzaldehyde.

Step 2

08.2 Identify the catalyst needed in this reaction. Give an equation to show how the catalyst is used to form the electrophile, [HCO]⁺.

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Answer

The catalyst needed for this reaction is Aluminum chloride (AlCl₃).

The formation of the electrophile can be illustrated as follows:

HCOCl+AlCl3[HCO]++[AlCl4]HCOCl + AlCl_3 \rightarrow [HCO]^+ + [AlCl_4]^-

Step 3

08.3 Outline the mechanism for the reaction of benzene with the electrophile, [HCO]⁺.

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Answer

The mechanism proceeds in several steps:

  1. Electrophilic Attack: An arrow from the benzene π electrons attacks the electrophile, [HCO]⁺, leading to the formation of a sigma complex (also known as an arenium ion).

  2. Proton Loss: A proton is lost from the sigma complex, restoring the aromaticity of the benzene ring.

  3. The final product is benzaldehyde with the release of a proton:

C6H5+HCO+C6H5CHOC_6H_5 + HCO^+ \rightarrow C_6H_5CHO

Key Points:

  • Initiation with the electrophile and deprotonation are crucial for restoring the aromaticity.

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